【发布时间】:2016-06-18 01:46:29
【问题描述】:
我正在使用 Ajax 加载项目,并且我使用了偏移量
JS:
var offset = 0;
$(".load-more").click(function() {
offset+=5;
$(this).addClass("spin");
$.ajax({
url: '/api/fetchitems.php?offset='+offset+'&sort='+sort,
success: function(data){
$(".load-more").before(data);
}
});
});
PHP/SQL:
$offset = intval($_GET["offset"]);
$stmt = $db->prepare(
"SELECT s.id,s.date,s.title,s.views,s.image,s.hidpi,s.width,s.description,u.display_name,u.avatar, s.hotness
FROM showcase AS s
INNER JOIN users AS u ON s.user_id = u.id
UNION ALL
SELECT q.id,q.date,q.title,q.views,0,0,0,q.text,u.display_name,u.avatar, q.hotness
FROM questions AS q
INNER JOIN users AS u ON q.user_id = u.id
ORDER BY hotness DESC
LIMIT :skip, 5
");
$stmt->bindParam(":skip",$offset);
$stmt->execute();
$items = $stmt->fetchAll();
$stmt = null;
我在执行时收到此错误:
Fatal error: Uncaught exception 'PDOException' with message 'SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near ''5', 5' at line 9' in **** Stack trace: #0 **** PDOStatement->execute() #1 {main} thrown in
当我在 phpMyAdmin 中运行 SQL 时,它运行良好。
【问题讨论】:
-
你能试试
$stmt->bindParam(":skip",intval($offset));吗? -
查看此网址stackoverflow.com/questions/15853266/…希望对您有所帮助
-
将查询“SELECT s.id.. 放入变量 $query 并回显 $query;exit; 然后在成功的 ajax 函数中提醒它或将其绑定到一个 div 中。复制该查询并执行在 mysql 中查看该查询中有什么问题。这将帮助您在没有任何帮助的情况下纠正错误