在数组中搜索最后 7 次出现

Question

我正在编写一个 php 代码来搜索文本文件中的不同变量....

数据在平面文件中逐行列出，数据列表格式为：

date | time | ip | geo-location (city) | //url

数据保存为日志文件（'track-log.txt'）

我目前的代码是：

$log_file = file_get_contents('track-log.txt');

$log_lines = explode(PHP_EOL, $log_file);

$log_lines = array_flip($log_lines);

unset($log_file);

这会将文本文件分成几行，然后将这些行向后翻转，以便它们在数组 $log_lines[*] 中作为文本文件的最后一行列出，首先显示为 $log_lines[0]

我需要计算有多少次“日期”是相同的......

<..... lots of logs here .... then .....>

jan 1st 2012 | data.....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 1st 2012 | data ....
jan 2nd 2012 | data ....
jan 2nd 2012 | data ....
jan 2nd 2012 | data .... <end log>

想象这是日志的结尾......我想：

$count[0] = 3 // last 3x dates are the same
$count[1] = 5 // the 5x dates before that are the same

所以我可以使用

echo $count[0];

在日志的“日期”部分显示最新值的数量。

我希望数组 $count[*] 停止列出 @ 7 个字符串....

$count[0]; ... 最多 ... $count[6]

这将显示最近 7 天的日志页数

....

extra info....日志中每一行的日期格式是

sunday, january 22, 2012 | 16:14:36 | 82.**.***.*** | bolton | //page_url

而且日期格式始终是一样的，因为它是一个脚本，在每个日志行上写入每个日期

....

Answer 1

这是解决问题的实用方法。

$lines = file('track-log.txt');

// This is a group discriminator
// It must return a 'key' which is what to group by,
// (in this case, by column 1 of the input line).
// as well as the orginal value.
function col1group($line){
    $key = trim(current(explode('|', $line, 2)));
    return array($key=>$line);
}

// $grouper is the group-descriminator function.
// we generate a new array with our keys to group by, then group them by
// key with array_merge_recursive
function array_groupby($array, $grouper) {
    return call_user_func_array('array_merge_recursive', array_map($grouper, $array));
}

//This is all lines, in file order, grouped by date.
$linesbydate = array_groupby($lines, 'col1group');

// if you want just the last seven:
$last7dates = array_slice($linesbydate, -7);
// if you want numeric keys:
$last7groups = array_values($last7dates);
// if you want them in reverse order:
$last7groupsReversed = array_reverse($last7groups);

// desired output
var_dump($last7groupsReversed);

使用你给这个程序的示例行将输出：

array(2) {
  [0]=>
  array(3) {
    [0]=>
    string(25) "jan 2nd 2012 | data ....
"
    [1]=>
    string(25) "jan 2nd 2012 | data ....
"
    [2]=>
    string(25) "jan 2nd 2012 | data ....
"
  }
  [1]=>
  array(5) {
    [0]=>
    string(25) "jan 1st 2012 | data.....
"
    [1]=>
    string(25) "jan 1st 2012 | data ....
"
    [2]=>
    string(25) "jan 1st 2012 | data ....
"
    [3]=>
    string(25) "jan 1st 2012 | data ....
"
    [4]=>
    string(25) "jan 1st 2012 | data ....
"
  }
}

如果您需要按其他标准进行分组，您可以通过创建另一个函数（如 col1group()）并将其传递给 array_groupby() 来实现。您还可以在此函数中更改行本身（例如，调用 rtrim() 删除换行符）。

Answer 2

这应该是诀窍......

<?php

$log_file = file_get_contents('track-log.txt');
$log_lines = explode(PHP_EOL, $log_file);
$log_lines = array_reverse($log_lines);
unset($log_file);
$count = array();
//loop through and itterate the count array using the date as the unique key
foreach($log_lines as $line){
    //explode this so we can use the date segment as a key
    $pieces = explode('|',$line);
    if (!isset($count[$pieces[0]])){
        //break out if we've hit the cap size
        if (count($count)>=7){break;}
        $count[$pieces[0]] = 0; 
    }
    $count[$pieces[0]]++;

}
//switch to a numeric index
$count = array_values($count);

?>

Answer 3

该函数更改键和值并且不反转数组..

 $log_lines = array_flip($log_lines);

这样做

$log_lines = array_reverse($log_lines);

生成计数数组

$count = array();
$index = -1;
$last_date = false;
foreach ($log_lines as $lines) {
     //sunday, january 22, 2012 | 16:14:36 | 82.**.***.*** | bolton | //page_url
     list($date,) = explode("|",$lines,2); //extract date 

     if ($last_date == $date)
          $count[$index]++;
     else {
         $last_date = $date;
         $index++;
         if ($index>=7) break; // 8. Date -> break
         $count[$index] = 1;
     }
}