HttpPost 500 错误。（SimpleCode）答案

【问题标题】：HttpPost 500 error.(SimpleCode)HttpPost 500 错误。（SimpleCode）
【发布时间】：2016-12-07 03:53:06
【问题描述】：

谁能告诉我这段代码有什么问题？基本上我正在尝试使用 Android 和 Php 将数据输入到表中。但我什至无法让 php 端工作，因为我收到 HTTP 错误 500，有人在这里看到错误吗？谢谢！

<?php
/* Connect to MySQL and select the database. */
 $con = mysql_connect($DB_SERVER,$DB_USERNAME,$DB_PASSWORD);

mysql_select_db ( $DB_DATABASE, $con ) or die ( “Database Selection Failed”     );




//$username = $_REQUEST['username'];
//$password = $_REQUEST['password'];
//$givenname = $_REQUEST['givenname'];
//$email = $_REQUEST['email'];
//$phonenumber = $_REQUEST['phonenumber'];

$username = isset($_POST[‘username’]) ? $_POST[‘username’] : ”;
$password = isset($_POST[‘password’]) ? $_POST[‘password’] : ”;
$givenname = isset($_POST[‘givenname’]) ? $_POST[‘givenname’] : ”;
$email = isset($_POST[‘email’]) ? $_POST[‘email’] : ”;
$phonenumber = isset($_POST[‘phonenumber’]) ? $_POST[‘phonenumber’] : ”;



$flag['code']=0;
if ($result = mysql_query ( “INSERT INTO demo VALUES(‘$username’,    ‘$password’, `$givenname`, `$email`, ‘$phonenumber’)”, $con )) {
$flag [‘code’] = 1;
echo “hi”;
}

echo (json_encode ( $flag )) ;
mysql_close ( $con );

?>

【问题讨论】：

这些引述在我看来很奇怪：‘, “, ”...

标签： php android mysql sql post

【解决方案1】：

是的。修正那些“聪明”的引号：

<?php
/* Connect to MySQL and select the database. */
 $con = mysql_connect($DB_SERVER,$DB_USERNAME,$DB_PASSWORD);

mysql_select_db ( $DB_DATABASE, $con ) or die ( "Database Selection Failed"     );




//$username = $_REQUEST['username'];
//$password = $_REQUEST['password'];
//$givenname = $_REQUEST['givenname'];
//$email = $_REQUEST['email'];
//$phonenumber = $_REQUEST['phonenumber'];

$username = isset($_POST['username']) ? $_POST['username'] : '';
$password = isset($_POST['password']) ? $_POST['password'] : '';
$givenname = isset($_POST['givenname']) ? $_POST['givenname'] : '';
$email = isset($_POST['email']) ? $_POST['email'] : '';
$phonenumber = isset($_POST['phonenumber']) ? $_POST['phonenumber'] : '';



$flag['code']=0;
if ($result = mysql_query ( "INSERT INTO demo VALUES('$username',    '$password', `$givenname`, `$email`, '$phonenumber')", $con )) {
$flag ['code'] = 1;
echo "hi";
}

echo (json_encode ( $flag )) ;
mysql_close ( $con );

?>

【讨论】：