获取 json 数据到 codeigniter 脚本的外部

Question

我正在使用 codeigniter 3.1.1 。我正在尝试将 json 数据放到 codeigniter 脚本之外。

Codeigniter Valid.php

if ( ! defined('BASEPATH')) exit('No direct script access allowed');

class Valid extends CI_Controller 
{

    public function __construct() 
    {
        parent::__construct();
        $this->load->model("user_model");

    }

    public function index() 
    {

    if($this->user->loggedin) {
        $json['success'] = "false"; 
    } else {
        $json['success'] = "true"; 
    }


   echo json_encode($json);

  }

}

Codeigniter Check.php 之外

$url = 'http://url.com/valid';

  $curl_handle = curl_init();
  curl_setopt($curl_handle,CURLOPT_URL,$url);
  curl_setopt($curl_handle,CURLOPT_RETURNTRANSFER,TRUE);
  curl_setopt($curl_handle, CURLOPT_HEADER, FALSE);
  curl_setopt ($curl_handle,CURLOPT_CONNECTTIMEOUT,0);
  curl_setopt($curl_handle, CURLOPT_FOLLOWLOCATION, TRUE);
  $json = curl_exec($curl_handle);
  curl_close($curl_handle);

    $json = json_decode($json);
    echo $json['success'];

我每次都收到$json['success'] = false。

Answer 1

像这样试试..

1.这里$this->user->loggedin不正确。我认为需要调用user_model的logged_in()函数。所以

public function index() 
    {
    $this->load->library('user');//loads user library
    if($this->user->loggedin()) {
        $json['success'] = "false"; 
    } else {
        $json['success'] = "true"; 
    }

2.在Check.php中。您必须将true参数与json_decode()一起传递才能转换为数组。

$json = json_decode($json,true);//converts into array
echo $json['success'];