Codeigniter 在 SQL 查询中使用 LIKE 和 WHERE答案

【问题标题】：Codeigniter using LIKE with WHERE in SQL queryCodeigniter 在 SQL 查询中使用 LIKE 和 WHERE
【发布时间】：2015-10-18 11:13:16
【问题描述】：

在 codeigniter 中，我有一个这样的查询：

    $this->db->select('*', false);
    $this->db->from('video as v');
    $this->db->where('v.start_date <=', 'NOW()', false);
    $this->db->like('v.title', $keywords);
    $this->db->or_like('v.title_tw', $keywords);
    $this->db->or_like('v.title_cn', $keywords);
    $query = $this->db->get();
    return $query->result_array();

在我的期望中：

start_date <= NOW **AND** title like $keywords OR title_tw like $keywords OR title_cn like $keywords

然而，结果却是：

start_date <= NOW **OR** title like $keywords OR title_tw like $keywords OR title_cn like $keywords

如何解决这个问题？非常感谢。

更新：

实际查询：

function search_video($keywords) {
    $this->db->select('v.*,t.name,t.name_tw,t.name_cn, t.image_url as profile_pic, COALESCE(b.duration, bt.duration, bc.duration) AS duration, COALESCE(b.thumbnail, bt.thumbnail, bc.thumbnail) as thumbnail', false);
    $this->db->from('video as v');
    $this->db->join('teacher as t', 'v.teacher_id = t.id');
    $this->db->join('video_tag as vt', 'v.id = vt.video_id', 'left');
    $this->db->join('brightcove as b', 'v.video = b.video_id', 'left');
    $this->db->join('brightcove as bt', 'v.video_tw = bt.video_id', 'left');
    $this->db->join('brightcove as bc', 'v.video_cn = bc.video_id', 'left');
    $this->db->where('v.is_delete', false);
    $this->db->where('v.start_date <=', 'NOW()', false);
    $this->db->like('v.title', $keywords);
    $this->db->or_like('v.title_tw', $keywords);
    $this->db->or_like('v.title_cn', $keywords);
    $this->db->or_like('vt.tag', $keywords);
    $this->db->group_by('v.id');
    $query = $this->db->get();
    return $query->result_array();
}

【问题讨论】：

标签： php mysql sql codeigniter

【解决方案1】：

对于 CodeIgniter 3.x：

您可以使用Query grouping 在查询中使用括号：

    $this->db->select('v.*,t.name,t.name_tw,t.name_cn, t.image_url as profile_pic, COALESCE(b.duration, bt.duration, bc.duration) AS duration, COALESCE(b.thumbnail, bt.thumbnail, bc.thumbnail) as thumbnail', false);
        $this->db->from('video as v');
        $this->db->join('teacher as t', 'v.teacher_id = t.id');
        $this->db->join('video_tag as vt', 'v.id = vt.video_id', 'left');
        $this->db->join('brightcove as b', 'v.video = b.video_id', 'left');
        $this->db->join('brightcove as bt', 'v.video_tw = bt.video_id', 'left');
        $this->db->join('brightcove as bc', 'v.video_cn = bc.video_id', 'left');
        $this->db->where('v.is_delete', false);
        $this->db->where('v.start_date <=', 'NOW()', false);
        $this->db->group_start();
        $this->db->like('v.title', $keywords);
        $this->db->or_like('v.title_tw', $keywords);
        $this->db->or_like('v.title_cn', $keywords);
        $this->db->or_like('vt.tag', $keywords);
        $this->db->group_end();
        $this->db->group_by('v.id');
        $query = $this->db->get();

对于 CodeIgniter 2.x：

虽然我没有对其进行测试，但我只是认为这应该可以工作：

$this->db->select('v.*,t.name,t.name_tw,t.name_cn, t.image_url as profile_pic, COALESCE(b.duration, bt.duration, bc.duration) AS duration, COALESCE(b.thumbnail, bt.thumbnail, bc.thumbnail) as thumbnail', false);
    $this->db->from('video as v');
    $this->db->join('teacher as t', 'v.teacher_id = t.id');
    $this->db->join('video_tag as vt', 'v.id = vt.video_id', 'left');
    $this->db->join('brightcove as b', 'v.video = b.video_id', 'left');
    $this->db->join('brightcove as bt', 'v.video_tw = bt.video_id', 'left');
    $this->db->join('brightcove as bc', 'v.video_cn = bc.video_id', 'left');
    $this->db->where('v.is_delete', false);
    $this->db->where('v.start_date <=', 'NOW()', false);
    $this->db->where("( v.title LIKE '%{$keywords}%'", null, FALSE);
    $this->db->or_like('v.title_tw', $keywords);
    $this->db->or_like('v.title_cn', $keywords);
    $this->db->where("OR vt.tag LIKE '%{$keywords}%' )", null, FALSE);
    $this->db->group_by('v.id');

【讨论】：

谢谢，但发现当前的 codeigniter 是 2.x.x，有什么解决方法吗？谢谢

【解决方案2】：

你可以这样试试：

$sql = SELECT * FROM video as v where v.start_date <= NOW() AND (v.title like ? OR v.title_tw like ? or v.title_cn like ?);
$query = $this->db->query($sql, array($keywords, $keywords, $keywords));

【讨论】：

非常感谢您的帮助。问题是实际查询非常复杂，因此使用单行查询可能不是那么简单
@user782104 - 好的，我看到您使用实际查询进行的新编辑。您仍然应该能够使用代表每个$keywords 输入的? 参数定义完整的SQL 查询，并使用db->query() 方法，因为其他所有内容都是静态的。无论如何，也许是一个选择。

【解决方案3】：

最后我创建了这样的查询，看起来工作正常：

function search_video($keywords) {
    $this->db->select('v.*,t.name,t.name_tw,t.name_cn, t.image_url as profile_pic, COALESCE(b.duration, bt.duration, bc.duration) AS duration, COALESCE(b.thumbnail, bt.thumbnail, bc.thumbnail) as thumbnail', false);
    $this->db->from('video as v');
    $this->db->join('teacher as t', 'v.teacher_id = t.id');
    $this->db->join('video_tag as vt', 'v.id = vt.video_id', 'left');
    $this->db->join('brightcove as b', 'v.video = b.video_id', 'left');
    $this->db->join('brightcove as bt', 'v.video_tw = bt.video_id', 'left');
    $this->db->join('brightcove as bc', 'v.video_cn = bc.video_id', 'left');
    $this->db->where("(v.is_delete = false AND v.start_date <= NOW()) AND (v.title LIKE '$keywords' OR  v.title_tw LIKE '$keywords' OR v.title_cn LIKE '$keywords' OR vt.tag LIKE '$keywords')");
    $this->db->group_by('v.id');
    $query = $this->db->get();
    return $query->result_array();
}

非常感谢您的帮助。

【讨论】：