(PHP) 如何使用与变量相关的字符串对多维数组进行排序？

Question

嘿，我的网站上有一个新功能，您可以在其中 通过在搜索输入中输入一些关键字来搜索 ya 项目。当然，我正在使用 ajax，我需要一个新函数来对数组进行排序或排序，该数组保存数据库中与用户在输入字段中写入的关键字相关的项目信息。 当用户点击例如“m”时，它应该以这种方式显示。

array [["836","123","Malaga - Ocean","1"],
       ["834","123","Malaga City","1"],
       ["838","123","DayZ - Novo Turm #1","0"],
       ["839","123","DayZ - Novo Turm #2","0"],
       ["840","123","DayZ - Novo Turm #3","0"]]

但如果我搜索以字母“m”开头的内容，则结果中应首先显示“Malaga City”和“Malaga - Ocean”。

我在不止一张表中搜索我收集它的关键字。但是，如果我在每个不同的表结果中添加数组，那么每次图片表首先得到结果时都会得到这样的结果。

MySql：

$sql_picture = "SELECT * FROM pictures [...] ORDER BY name LIMIT 5";
$sql_videos = "SELECT * FROM videos [...] ORDER BY name LIMIT 5";
$sql_audio = "SELECT * FROM audio [...] ORDER BY name LIMIT 5";
$sql_documents = "SELECT * FROM documents [...] ORDER BY name LIMIT 5";

PHP：

$collectedDataName = array();

for($i = 0; $i < count($collectData); $i++){
    $collectedDataName[$i] = $collectData[$i][2];
}

$collectData_lowercase = array_map('strtolower', $collectedDataName);

array_multisort($collectData_lowercase, SORT_ASC, SORT_STRING, $collectedDataName);

$returnData = array();

for($j = 0; $j < 5; $j++){
    for($i = 0; $i < count($collectData); $i++){
        if($collectData[$i][2] === $collectedDataName[$j]){
            $returnData[$j] = $collectData[$i];
        }
    }
}

echo json_encode($returnData);

结果：

array [["838","123","DayZ - Novo Turm #1","0"],
      ["839","123","DayZ - Novo Turm #2","0"],
      ["840","123","DayZ - Novo Turm #3","0"],
      ["836","123","Malaga - Ocean","1"],
      ["834","123","Malaga City","1"]]

如何按与变量相关的字符串值对多维数组进行排序？

Answer 1

您想根据输入值对多维数组进行排序，有点像我们在 sql 中使用

select * from table where column like 'inputValue%'

这是一个仅基于php的解决方案

$inputvalue = 'm';
$inputvalue = strtolower($inputvalue);

$collectData = [["838","123","DayZ - Novo Turm #1","0"],
             ["834","123","Malaga City","1"],
             ["839","123","DayZ - Novo Turm #2","0"],         
             ["836","123","Malaga - Ocean","1"],
             ["840","123","DayZ - Novo Turm #3","0"],
            ];

/*
we use strpos to check if the input value is contained in the strings array, if not we use levenshtein to calculate the distance between them.*/

$distances = array();
$positions = array();
for ($i=0; $i < count($collectData); $i++) {    
  $current_val = strtolower($collectData[$i][2]);
  if (strpos($current_val, $inputvalue)!==false)
    $distance = strpos($current_val, $inputvalue);
  else
    $distance = levenshtein($inputvalue, $current_val);

  $distances[] = $distance;        
  $positions[] = array("distance"=>$distance, "position"=>$i);        
}

/*we sort distances*/
sort($distances);

/* we reorder collectData based on distances sort  */
$returnData = array();
for ($j=0; $j<count($distances); $j++) {
  for ($k=0; $k<count($positions); $k++) {
    $val = $collectData[$positions[$k]["position"]];

    if ($distances[$j]==$positions[$k]["distance"] && !in_array($val, $returnData)) {
        $returnData[] = $val;
        break;
    }
  }
}

return $returnData;

levenshtein php 文档在这里：levenshtein function

Answer 2

array_multisort 可以帮忙吗？您是否打算返回仅以“m”开头的结果？

<?php
// create an array of the "column" to sort on...
foreach ($returnData as $row)  
{
    $test[] = $row[2];
}

// sort it...
array_multisort($test, SORT_DESC, $returnData);
?>

Answer 3

您的问题有两种可能的解决方案：

1. SQL 解决方案

让数据库使用联合为您进行排序。例如：

SELECT
   id1, 
   id2,
   name
FROM
   (
       (SELECT id1, id2, name FROM pictures WHERE something=... ORDER BY name LIMIT 5)
       UNION ALL
       (SELECT id1, id2, name FROM videos WHERE something=... ORDER BY name LIMIT 5)
    ) AS q
ORDER BY
   name

2。 PHP解决方案

您正在进行非标准排序，因此您需要使用usort，它采用比较器函数来比较两个数组项：

$allData = array_merge($sql_picture, $sql_video, ...);
usort($allData, function($a, $b) { return strcmp($a[2], $b[2]); });