【发布时间】：2016-02-08 01:52:27
【问题描述】：
我想要实现的是，它将在数组中循环。然后它将查看数组中的项目是否在三个点上相同：product_id、size 值和 color 值。 我想创建一个列出项目的新数组，我唯一不想要的是重复的值。我想要重复的值，如果它们在这三个点上相同，那么数量将一起计算。就像我有 3 个相同的产品 ID 相同的尺寸和相同的颜色，并且这三个我在我的新数组中订购了 3 个项目，这只是站立 1 次，数量将为 9。所以我的新数组中不会有重复的值数组。
当前循环
foreach($orders as $key => $order){
foreach($order['orderProducts'] as $key => $value){
echo '<pre>';
print_r($value['attributes']);
echo '</pre>';
}
}
产生以下数组
Array
(
[id] => 2
[product_id] => 4
[order_id] => 2
[name] => swag3
[description] => haha
[price] => 19.95
[proceeds] => 10.00
[quantity] => 2
[attributes] => [{"id":1,"name":"Size","value":"XS","active":1},{"id":8,"name":"Color","value":"Wit","active":1}]
)
Array
(
[id] => 3
[product_id] => 3
[order_id] => 3
[name] => swag2
[description] => lol
[price] => 19.95
[proceeds] => 10.00
[quantity] => 2
[attributes] => [{"id":2,"name":"Size","value":"S","active":1},{"id":7,"name":"Color","value":"Zwart","active":1}]
)
Array
(
[id] => 4
[product_id] => 3
[order_id] => 4
[name] => swag2
[description] => lol
[price] => 19.95
[proceeds] => 10.00
[quantity] => 1
[attributes] => [{"id":2,"name":"Size","value":"S","active":1},{"id":7,"name":"Color","value":"Zwart","active":1}]
)
我正在寻找的东西..
Array
(
[id] => 2
[product_id] => 4
[order_id] => 2
[name] => swag3
[description] => haha
[price] => 19.95
[proceeds] => 10.00
[quantity] => 2
[attributes] => [{"id":1,"name":"Size","value":"XS","active":1},{"id":8,"name":"Color","value":"Wit","active":1}]
)
Array
(
[id] => 3
[product_id] => 3
[order_id] => 3
[name] => swag2
[description] => lol
[price] => 19.95
[proceeds] => 10.00
[quantity] => 3
[attributes] => [{"id":2,"name":"Size","value":"S","active":1},{"id":7,"name":"Color","value":"Zwart","active":1}]
)
解决方案 请注意，它是作为前端的刀片 php。
后端
$order // is the array with products
$items = [];
foreach($orders as $key => $order){
foreach($order['orderProducts'] as $op){
$i = [
'product'=> Product::findOrFail($op->product_id)->toArray(),
'attributes' =>$op->attributes,
'quantity'=>$op->quantity
];
$matchedResult = false;
$count = count($items);
for($a = 0; $a < $count; $a++){
// Items with the same product_id in the $item array
if($items[$a]['product']['id'] == $i['product']['id']){
//check if the attributes are also the same
if($items[$a]['attributes'] === $i['attributes']){
// The attributes ar ethe same so up the quantity
$items[$a]['quantity'] += $i['quantity'];
$matchedResult = true;
continue; // If its right there are no other matches
}
}
}
if($matchedResult === false){
// only push item if there is not a match.
$items[] = $i;
}
}
}
前端
<div class="table-responsive">
<table class="table table-striped">
<thead>
<tr>
<th>Product</th>
<th>quantity</th>
</tr>
</thead>
<tbody>
@foreach($items as $item)
<tr>
<td>{{$item['product']['name']}}
@if(count($item['attributes']) > 0) <small>
@foreach($item['attributes'] as $att)
{{$att['name']}} - {{$att['value']}}
@endforeach
</small>
@endif</td>
<td>{{$item['quantity']}}</td>
</tr>
@endforeach
</tbody>
</table>
</div>
【问题讨论】：
-
没有内置函数可以做到这一点。你必须编写自己的循环来做到这一点。
-
往正确的方向推进：嵌套循环。
foreach ($orders as $key1 => $value1) { foreach ($orders as $key2 => $value2) { test if they're the same } } -
@AbraCadaver 这与大小和颜色属性不匹配。
-
@Barmar：是的，只是重读。
-
您需要获取该属性 JSON 对象并将元素添加到另一个相关表中。如果你现在这样做，你会为自己省去很多麻烦。