单击多个链接时如何从会话中获取先前的链接值

Question

我正在尝试使用 AJAX 和 PHP 中的会话来获取以前单击的链接值。但我只得到当前值。这是我正在使用的代码。

<?php
session_start();
//session_destroy();

if(isset($_POST['getpage'])){
    $page = $_POST['pagename'];
    $_SESSION['current'] = $page;

    if(!isset($_SESSION['previous'])){
        $_SESSION['previous'] = "null";
        $_SESSION['previousnew'] = $_SESSION['current'];
    }
    elseif($_SESSION['previous'] == "null"){
        $_SESSION['previous'] = $_SESSION['previousnew'];
        $_SESSION['previousnew'] = $_SESSION['current'];
    }
    else
        $_SESSION['previous'] = $_SESSION['previousnew'];

    print_r($_SESSION);
    exit();
}

$value = 5;

$arr = array("file1","file2","file3","file4");
foreach ( $arr as $k => $v){
    echo "<a href='".$v.".php' onclick='return createpage(\"$v\");'> ".$v." </a><br>";
}
?>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
function createpage (page){
    var name = page+".php";
    $.post("pageone.php",{getpage : 1,pagename:name},function(data){
        alert(data);
    });
    return false;
}
</script>

更新

<?php
session_start();
//session_destroy();

if(isset($_POST['getpage'])){
$page = $_POST['pagename'];
$_SESSION['current'] = $page;

if(!isset($_SESSION['previous'])){

$_SESSION['previous'] = "null";
$_SESSION['previousnew'] = $_SESSION['current'];
}
elseif($_SESSION['previous'] == "null"){
 $_SESSION['previous'] = $_SESSION['previousnew'];
 $_SESSION['previousnew'] = $_SESSION['current'];
}
else $_SESSION['previous'] = $_SESSION['previousnew'];



$file_pointer = fopen( $_POST['pagename'], 'w' );

$string = '<?php include_once("pageone.php");?>
<?php $var = "'.$_POST["pagename"].'";?>
<?php echo $var;?>
<?php echo "'.$_SESSION["previous"].'";?>
';

fwrite( $file_pointer, $string );

fclose($file_pointer);
exit();
}



$value = 5;

$arr = array("file1","file2","file3","file4");


foreach ( $arr as $k => $v){
echo "<a href='".$v.".php' onclick='return createpage(\"$v\");'> ".$v." </a><br>";
}

?>
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.3/jquery.min.js"></script>
<script>
function createpage (page){
var name = page+".php";
$.post("pageone.php",{getpage : 1,pagename:name},function(data){
    //alert(data);
});
return true;
}
</script>

在这里，我正在创建新页面，但我无法获取我之前点击的内容。这就是我想要实现的目标。

Answer 1

尝试会话存储：

function createpage (page){
if (sessionStorage.getItem('href')) {
alert(sessionStorage.getItem('href'));
}
sessionStorage.setItem('href', $(this).attr('href'));
}