【发布时间】:2014-11-25 00:08:33
【问题描述】:
我正在做在线能力倾向测试,它将从数据库中随机抽取2个问题并显示在网页上以供回答。
问题是它没有在数据库中正确存储值(在将问题和答案存储到数据库中时,它变得混乱,有些甚至没有存储)。谁能帮我解决这个问题,
下面的代码是从候选人那里得到答案(简单的演示只选择了 2 个随机问题)。
<form id="form1" name="quest" method="POST" action="" >
<?php
$connect = mysql_connect("localhost","root","")
or die(mysql_error());
$sel=mysql_select_db("demo");
$query = mysql_query("SELECT * FROM `microsoftq` ORDER BY RAND() LIMIT 2 ");
rows1 = mysql_fetch_array($query);
$q1 = $rows1['QNo'];
$qus1 = $rows1['Question'];
$a1 = $rows1['Opt1'];
$b1 = $rows1['Opt2'];
$c1 = $rows1['Opt3'];
$d1 = $rows1['Opt4'];
$ans1 = $rows1['Ans'];
echo " <b>Question:-<br></b>$qus1 <br><br>";
echo " <input type=radio name = 'answer$q1' value = '$a1'></input>$a1    <br>";
echo " <input type=radio name = 'answer$q1' value = '$b1'></input>$b1    <br>";
echo " <input type=radio name = 'answer$q1' value = '$c1'></input>$c1     <br>";
echo " <input type=radio name = 'answer$q1' value = '$d1'></input>$d1 <br><br> ";
$rows2 = mysql_fetch_array($query);
$q2 = $rows2['QNo'];
$qus2 = $rows2['Question'];
$a2 = $rows2['Opt1'];
$b2 = $rows2['Opt2'];
$c2 = $rows2['Opt3'];
$d2 = $rows2['Opt4'];
$ans2 = $rows2['Ans'];
echo " <b>Question:-<br></b>$qus2<br> <br>";
echo " <input type=radio name = 'answer$q2' value = '$a2'></input>$a2    <br>";
echo " <input type=radio name = 'answer$q2' value = '$b2'></input>$b2    <br>";
echo " <input type=radio name = 'answer$q2' value = '$c2'></input>$c2    <br> ";
echo " <input type=radio name = 'answer$q2' value = '$d2'></input>$d2 <br><br> ";
}
?>
<input type="submit" id="submit_id" name="SUBMIT" value="SUBMIT">
</form>
下一部分是在用户点击提交按钮后将它们存储到数据库中。
if (isset($_POST['SUBMIT']))
{
$connect = mysql_connect("localhost","root","")
or die(mysql_error());
$sel=mysql_select_db("demo");
$opt1=$_POST["answer$q1"]; // Problem is here
$id1=array("$q1","$opt1");
if($ans1==$opt1) // Out Correcting answer part
{
$val1="ct";
}
else
{
$val1="wg";
}
$opt2=$_POST["answer$q2"]; // Problem is here
$id2=array("$q2","$opt2");
if($ans2==$opt2) // Out Correcting answer part
{
$val2="ct";
}
else
{
$val2="wg";
}
mysql_query("insert into $username values('$id1[0]','$id1[1]','$val1')")
or die(mysql_error());
mysql_query("insert into $username values('$id2[0]','$id2[1]','$val2')")
or die(mysql_error());
?>
【问题讨论】:
标签: php html mysql sql database