如何将数据存储到存在行

Question

我编写代码用于在插入新数据时将预订数据插入到我的数据库中，它将创建新行，因此我得到重复的数据，因此如果 schedules_id 等于存在 schedules_id 则我需要存储数据 将座位数据存储到该表中数组格式，我就是这样做的。

$booking = new Bookings();
        $booking->users_id = 4;
        $booking->schedules_id = $schedules_id;
        $booking->buses_id = $buses_id;
        $booking->routes_id = $routes_id;
        $booking->seat = implode(',', $seat);
        $booking->price = $request->price;
        $booking->profile = 'pending';

Answer 1

您可以在模型上使用updateOrCreate 方法，所以试试这个：

$booking = Bookings::updateOrCreate(
    ['schedules_id' => $schedules_id, 'users_id' => 4 ], // match the row based on this array
    [ // update this columns
        'buses_id' => $buses_id,
        'routes_id' => $routes_id,
        'seat' => json_encode($seat),
        'price' => $request->price,
        'profile' => 'pending',
    ]

);

Answer 2

$booking = Bookings::firstOrCreate(
           ['schedules_id' => $schedules_id ],// row to test if schedule id matches existing schedule id
           [ // update this columns
              'buses_id' => $buses_id,
              'routes_id' => $routes_id,
              'seat' => implode(',', $seat),
              'price' => $request->price,
              'profile' => 'pending',
           ]);

你可以使用这个 firstORcreate laravel 方法。有关其用法的更多说明，请参见此 stackoverflow 页面。

First Or Create

但是，如果您想将数据存储为数组，您可以在数据库中为数据创建文本或 json 字段，并使用 eloquent 序列化来处理它。 https://laravel.com/docs/5.8/eloquent-serialization

另一个堆栈溢出示例，其中回答了有关在 json 中存储数据的问题是 Laravel : How to store json format data in database?

Answer 3

试试这个

假设 Bookings 是模型

$matchThese = ['schedules_id' => $schedules_id];

Bookings::updateOrCreate($matchThese,[
    'seat'  => implode(',', $seat)
]);

或

$data = $request->all();

$data['seat'] = implode(',', $seat);

$matchThese = ['schedules_id' => $schedules_id];

Bookings::updateOrCreate($matchThese, $data);

确保您在 Bookings 模型中的 $fillable 中添加了列

你可以在你的模型中进行铸造

protected $casts    = [
        'seat'           =>  'array',
    ];

如果你使用数组转换，那么$data['seat'] 应该是数组