将此字符串（PHP 数组）转换为 JSON 编码字符串的最简单方法是什么？

Question

我的错误日志向我发送了一封电子邮件，其中包含大量数据，这些数据存储在用户会话中。这个数组应该已经转换为 JSON 编码的字符串并存储在我的数据库中，但出现了问题。如果我将数据作为文本字符串，那么转换回 JSON 并保存回我的数据库的最快方法是什么。这是数组中一些数据的示例。请记住：我将其作为文本字符串和电子邮件，而不是实际数组。电子邮件中的内容周围有<pre> 标签。

            [customer_firstname] => James
            [customer_lastname] => Smith
            [customer_address1] => 
            [customer_postcode] => AB12CD
            [customer_address2] => 
            [customer_address3] => 
            [customer_address4] => 
            [customer_town] => London
            [customer_county] => 
            [customer_country] => UK

Answer 1

我能想到的最简单的方法是在输出上添加一个简单的str_replace，将其转换为一个数组，您可以将其复制粘贴到 PHP 脚本中，然后再转换为 JSON。

<?php
  $errorInfo = "[customer_firstname] => James
        [customer_lastname] => Smith
        [customer_address1] => 
        [customer_postcode] => AB12CD
        [customer_address2] => 
        [customer_address3] => 
        [customer_address4] => 
        [customer_town] => London
        [customer_county] => 
        [customer_country] => UK";

  echo str_replace(["[", "]", "=> ", "\n"], ["'", "'", "=>\"", "\",\n<br />"],  $errorInfo);
?>

输出：

'customer_firstname' =>"James", 
'customer_lastname' =>"Smith", 
'customer_address1' =>"", 
'customer_postcode' =>"AB12CD", 
'customer_address2' =>"", 
'customer_address3' =>"", 
'customer_address4' =>"", 
'customer_town' =>"London", 
'customer_county' =>"", 
'customer_country' =>"UK

注意最后一个右引号漏掉了……需要自己加这个或者在str_replace后面加

然后加上大括号并赋值：

$error = [
  'customer_firstname' =>"James", 
  'customer_lastname' =>"Smith", 
  'customer_address1' =>"", 
  'customer_postcode' =>"AB12CD", 
  'customer_address2' =>"", 
  'customer_address3' =>"", 
  'customer_address4' =>"", 
  'customer_town' =>"London", 
  'customer_county' =>"", 
  'customer_country' =>"UK"];

简单：

echo json_encode($error);