【发布时间】:2011-04-07 22:58:11
【问题描述】:
我有以下示例代码,我从欧洲议会网站下载了关于给定立法提案的 pdf:
编辑:我最终只是获得了链接并将其提供给 adobes 在线转换工具(请参见下面的代码):
import mechanize
import urllib2
import re
from BeautifulSoup import *
adobe = "http://www.adobe.com/products/acrobat/access_onlinetools.html"
url = "http://www.europarl.europa.eu/oeil/search_reference_procedure.jsp"
def get_pdf(soup2):
link = soup2.findAll("a", "com_acronym")
new_link = []
amendments = []
for i in link:
if "REPORT" in i["href"]:
new_link.append(i["href"])
if new_link == None:
print "No A number"
else:
for i in new_link:
page = br.open(str(i)).read()
bs = BeautifulSoup(page)
text = bs.findAll("a")
for i in text:
if re.search("PDF", str(i)) != None:
pdf_link = "http://www.europarl.europa.eu/" + i["href"]
pdf = urllib2.urlopen(pdf_link)
name_pdf = "%s_%s.pdf" % (y,p)
localfile = open(name_pdf, "w")
localfile.write(pdf.read())
localfile.close()
br.open(adobe)
br.select_form(name = "convertFrm")
br.form["srcPdfUrl"] = str(pdf_link)
br["convertTo"] = ["html"]
br["visuallyImpaired"] = ["notcompatible"]
br.form["platform"] =["Macintosh"]
pdf_html = br.submit()
soup = BeautifulSoup(pdf_html)
page = range(1,2) #can be set to 400 to get every document for a given year
year = range(1999,2000) #can be set to 2011 to get documents from all years
for y in year:
for p in page:
br = mechanize.Browser()
br.open(url)
br.select_form(name = "byReferenceForm")
br.form["year"] = str(y)
br.form["sequence"] = str(p)
response = br.submit()
soup1 = BeautifulSoup(response)
test = soup1.find(text="No search result")
if test != None:
print "%s %s No page skipping..." % (y,p)
else:
print "%s %s Writing dossier..." % (y,p)
for i in br.links(url_regex="file.jsp"):
link = i
response2 = br.follow_link(link).read()
soup2 = BeautifulSoup(response2)
get_pdf(soup2)
在 get_pdf() 函数中,我想将 pdf 文件转换为 python 中的文本,以便我可以解析文本以获取有关立法程序的信息。谁能解释一下这是怎么做到的?
托马斯
【问题讨论】:
-
[在此处插入关于
import *的标准投诉] -
我知道关于污染命名空间的标准投诉,但在上述情况下,这似乎是一个非常理论上的投诉;)
-
这个blog可以帮助选择最好的库。