嗨，我正在 python 中尝试硒

Question

您好，我正在 python 中试验 selenium，我基本上想加载这个网站 https://www.jdsports.co.uk/c/footwear/?max=72 并获取每个产品的名称和价格。如果其中任何一个让您感到困惑，我也在使用 tkinter GUI，例如我运行它，它加载主菜单我单击我想要查看的部分，它打开浏览器，现在它加载然后我遇到每次都出现这个错误

Exception in Tkinter callback
Traceback (most recent call last):
  File "E:\Python\lib\tkinter\__init__.py", line 1883, in __call__
    return self.func(*args)
  File "C:\Users\James\Desktop\WebScraper\webscraper.py", line 34, in <lambda>
    scrapeBtn = tkinter.Button(secndmenu, text='scrape', command=lambda url=url:scrape(url,secndmenu))
  File "C:\Users\James\Desktop\WebScraper\webscraper.py", line 49, in scrape
    print(products.get_attribute('text'))
AttributeError: 'list' object has no attribute 'get_attribute'

这里是代码

#imports
from selenium import webdriver
import tkinter

#Window Calls
home = tkinter.Tk()
home.title("Home")
home.geometry('500x500')

urlselec=''

def shopClothing():
    urlselec="https://www.jdsports.co.uk/c/clothing/?max=72"
    url = urlselec
    return url, scrapeOrAuto(url)

def shopFootWare():
    urlselec='https://www.jdsports.co.uk/c/footwear/?max=72'
    url = urlselec
    return url, scrapeOrAuto(url)

def shopAccessories():
    urlselec='https://www.jdsports.co.uk/c/accessories/'
    url = urlselec
    return  url, scrapeOrAuto(url)


def scrapeOrAuto(url):
    home.withdraw()
    secndmenu = tkinter.Tk()
    secndmenu.title('Choose')
    secndmenu.geometry('300x300')
    url = url
    scrapeBtn = tkinter.Button(secndmenu, text='scrape', command=lambda url=url:scrape(url,secndmenu))

    scrapeBtn.pack()
    secndmenu.mainloop()

def scrape(url,secndmenu):
    secndmenu.withdraw()
    scraperAlert = tkinter.Tk()
    scraperAlert.title('Alert!')
    scraperAlert.geometry('300x200')

    tkinter.Label(scraperAlert,text='Scraping!').pack()
    browser = webdriver.Chrome()
    browser.get(url)
    products = browser.find_elements_by_class_name("productListItem ")
    print(products.get_attribute('text'))
    # soruce = browser.page_source
    print(products)

    return print('scraped')

#Buttons
clothing = tkinter.Button(anchor='center',text="Clothing", command =shopClothing)
footware = tkinter.Button(anchor='center',text='Footware', command=shopFootWare)
accessories = tkinter.Button(text='Accessories', command=shopAccessories)



#WindowCompile
clothing.pack()
footware.pack()
accessories.pack()
home.mainloop()

Answer 1

仅阅读错误消息，不知道有关 TkInter 或 Selenium 的任何特殊信息，告诉我 products 是 list，而在 Python 中，您不能在列表中调用 get_attribute。

我假设products 是一个类名为productListItem 的浏览器元素列表，因此您想要掌握该列表的元素，然后调用@987654326 @那些！

也许

for product in products:
  print(product.get_attribute('text'))

可能会起作用。