将 XML 解析为谷歌地图以创建多个标记

Question

今天的问题是这样的：

    GDownloadUrl("http://www.mysite/map.php", 
    
    function(data) {
      var xml = GXml.parse(data);
      //var markers = xml.documentElement.getElementsByTagName("marker");
     
      //for (var i = 0; i < markers.length; i++) {
        //var address = new GLatLng(parseFloat(markers[i].getAttribute("location")));
        
        //var latlong = address.split(",");            
        
        //var latlongtomap = new GLatLng(parseFloat(latlong[0]), parseFloat(latlong[1]));
       
        var latlongtomap = new GLatLng(51.477711,-3.176555);

        var marker = createMarker(latlongtomap);
        
        map.addOverlay(marker);
     // }
    });
  }
}

如果我运行它，它将获取纬度和经度坐标并为我在地图上创建一个标记。但是，如果我尝试从我的 php 脚本中获取“位置”选项卡（使用所有注释掉的代码）：

map.php

<?php
mysql_connect("", "", "") or die(mysql_error());
mysql_select_db("") or die(mysql_error());

$query = "SELECT MAPADDRESS FROM report";
$result = mysql_query($query) or die(mysql_error());

$doc = new DomDocument('1.0');
$node = $doc->createElement("markers");
$parnode = $doc->appendChild($node);
header("Content-type: text/xml");

while($row = mysql_fetch_array($result)){
   $node = $doc->createElement("marker");
   $newnode = $parnode->appendChild($node);
   $newnode->setAttribute("location", $row['MAPADDRESS']);
}
print $doc->saveXML();
?>

结果如下：

<markers>
   <marker location="51.477711,-3.176555"/>
   <marker location="51.472512,-3.187527"/>
   <marker location="51.471057,-3.186263"/>
   <marker location="51.473261,-3.192219"/>
</markers>

为什么代码不能正确读取这个 PHP？

Answer 1

试试这个：

var latlong = markers[i].getAttribute("location").split(",");            
var latlongtomap = new GLatLng(parseFloat(latlong[0]), parseFloat(latlong[1]));