XML 处理脚本只列出一个元素，但要列出多个元素

Question

我编写了一个简单的 Python 脚本来打印所有与父元素属性关联的包名称的 XML 数据：Security Advisory。

import xml.etree.ElementTree as ET
tree = ET.parse('errata.xml')
root = tree.getroot()
for security in root.findall("*[@type='Security Advisory']"):
    packages = security.find('packages')
    print(packages.text)

XML 数据位于here

然而，脚本只打印出第一个包名，但有多个包名。我将如何获取所有属于父属性的包名称：Security Advisory？

Answer 1

在下面（似乎有效）

import xml.etree.ElementTree as ET

import requests

r = requests.get('https://cefs.b-cdn.net/6010e333a44911e24b5112e23acbb346ae15f7b7/errata.latest.xml')
if r.status_code == 200:
    root = ET.fromstring(r.content)
    sec_elements = [e for e in root.findall("*[@type='Security Advisory']") if
                    e.find('os_release') is not None and int(e.find('os_release').text) > 6]
    for ele in sec_elements:
        packages = ele.findall('./packages')
        for p in packages:
            print(p.text)