【发布时间】:2011-05-26 13:51:35
【问题描述】:
我在使用 sax parser 解析本地 xml 文件时遇到问题。解析时抛出异常。
*org.apache.harmony.xml.ExpatParser$ParseException: At line 7, column 247: not well-formed (invalid token)
org.apache.harmony.xml.ExpatParser.parseFragment(ExpatParser.java:507)
org.apache.harmony.xml.ExpatParser.parseDocument(ExpatParser.java:492)
org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:308)
org.apache.harmony.xml.ExpatReader.parse(ExpatReader.java:264)*
try {
String path = Environment.getExternalStorageDirectory() + "/FlightGuide/"+stateName+"/contents.xml";
File file = new File(path);
SAXParserFactory parserFactory=SAXParserFactory.newInstance();
SAXParser saxParser=parserFactory.newSAXParser();
XMLReader reader=saxParser.getXMLReader();
AirportHandler airportHandler = new AirportHandler();
reader.setContentHandler(airportHandler);
reader.parse(new InputSource(new InputStreamReader(new FileInputStream(file))));
statePackage = airportHandler.getpaStatePackage();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (ParserConfigurationException e) {
e.printStackTrace();
} catch (SAXException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
请任何人弄清楚我在做什么?还有其他解析本地xml文件的方法吗?如果是这样,请给我一些示例代码。
谢谢你, 斯里尼瓦斯
【问题讨论】:
标签: android xml-parsing saxparser