关于 SAXparseException: prolog 中不允许内容

Question

我正在使用 glassfish 服务器，但不断出现以下错误：

Caused by: org.xml.sax.SAXParseException: Content is not allowed in prolog.
        at com.sun.enterprise.deployment.io.DeploymentDescriptorFile.read(DeploymentDescriptorFile.java:304)
        at com.sun.enterprise.deployment.io.DeploymentDescriptorFile.read(DeploymentDescriptorFile.java:226)
        at com.sun.enterprise.deployment.archivist.Archivist.readStandardDeploymentDescriptor(Archivist.java:480)
        at com.sun.enterprise.deployment.archivist.Archivist.readDeploymentDescriptors(Archivist.java:305)
        at com.sun.enterprise.deployment.archivist.Archivist.open(Archivist.java:213)
        at com.sun.enterprise.deployment.archivist.ApplicationArchivist.openArchive(ApplicationArchivist.java:813)
        at com.sun.enterprise.instance.WebModulesManager.getDescriptor(WebModulesManager.java:395)
        ... 65 more

Answer 1

查看此链接

http://mark.koli.ch/2009/02/resolving-orgxmlsaxsaxparseexception-content-is-not-allowed-in-prolog.html

简而言之，一些 XML 文件在前面（<?xml ...?> 之前）包含三字节模式（0xEF 0xBB 0xBF），这是 UTF-8 字节顺序标记。 java 的默认 XML 解析器无法处理这种情况。

快速而肮脏的解决方案是删除 XML 文件前面的空白：

String xml = "<?xml ...";
xml = xml.replaceFirst("^([\\W]+)<","<");

注意 String.trim() 不够，因为它只修剪有限的空白字符。