将xml转换为数据框答案

【问题标题】：Converting xml into dataframe将xml转换为数据框
【发布时间】：2021-03-25 03:43:21
【问题描述】：

我正在尝试将我的 xml-request（参见下面的示例）转换为 pandas-dataframe，但它没有按应有的方式工作，我不知道为什么。

xml 请求示例

<workingTimes>
<day>
    <date>2015-09-21</date>
    <dayOfWeek>Mon</dayOfWeek>
    <employee>
        <firstName>Albert</firstName>
        <lastName>Grimaldi</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
    <employee>
        <firstName>Max</firstName>
        <lastName>Mustermann</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber>12346</personnelNumber>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
</day>
<day>
    <date>2015-09-22</date>
    <dayOfWeek>Tue</dayOfWeek>
    <employee>
        <firstName>Albert</firstName>
        <lastName>Grimaldi</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
    <employee>
        <firstName>Max</firstName>
        <lastName>Mustermann</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber>12346</personnelNumber>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
</day>
</workingTimes>

代码：

import pandas as pd
from xml.etree import ElementTree as et
...
r = requests.get(api_url, headers=headers)

root = et.fromstring(r.content)

df_cols, rows = ['date', 'dayOfWeek', 'firstName', 'lastName', 'duration', 'costCenter'], []
for child in root:
    s_date = child.attrib.get("date")
    s_dayOfWeek = child.attrib.get("dayOfWeek")
    s_firstName = child.find("firstName").text if child is not None else None
    s_lastName = child.find("lastName").text if child is not None else None
    s_duration= child.find("duration").duration if child is not None else None
    s_costCenter= child.find("costCenter").text if child is not None else None

    rows.append({'date': s_date, 'dayOfWeek': s_dayOfWeek, 'firstName': s_firstName, 'lastName': 
        s_lastName, 'duration': s_duration, 's_costCenter': costCenter})

df_xml = pd.DataFrame(rows, columns=df_cols)

这是纪录片的一部分：

谁能告诉我我做错了什么？

【问题讨论】：

有什么问题？请注意，date 和 dayOfWeek 与您要查找的属性不在同一级别。
@balderman 我得到一个空的数据框，即使我知道我的 xml 中有条目！这就像我无法进入子元素（是这样称呼的吗？）。
首先测试我发布的代码并填充 df。如果它有效 - 扩展它。

标签： python xml dataframe elementtree

【解决方案1】：

见下文（只需扩展代码以收集更多元素）

import xml.etree.ElementTree as ET

XML = '''<workingTimes>
<day>
    <date>2015-09-21</date>
    <dayOfWeek>Mon</dayOfWeek>
    <employee>
        <firstName>Albert</firstName>
        <lastName>Grimaldi</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
    <employee>
        <firstName>Max</firstName>
        <lastName>Mustermann</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber>12346</personnelNumber>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
</day>
<day>
    <date>2015-09-22</date>
    <dayOfWeek>Tue</dayOfWeek>
    <employee>
        <firstName>Albert</firstName>
        <lastName>Grimaldi</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
    <employee>
        <firstName>Max</firstName>
        <lastName>Mustermann</lastName>
        <login xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:nil="true"/>
        <personnelNumber>12346</personnelNumber>
        <duration>00:00:00</duration>
        <rest mandatory="00:00:00">00:00:00</rest>
        <costCenter>AB-1234</costCenter>
    </employee>
</day>
</workingTimes>'''
data = []
root = ET.fromstring(XML)
days = root.findall('.//day')
for d in days:
    emp_lst = d.findall('employee')
    for e in emp_lst:
        # TODO collect more data
        data.append(
            {'day': d.find('date').text, 'first_name': e.find('firstName').text, 'last_name': e.find('lastName').text})
for entry in data:
    print(entry)

输出

{'day': '2015-09-21', 'first_name': 'Albert', 'last_name': 'Grimaldi'}
{'day': '2015-09-21', 'first_name': 'Max', 'last_name': 'Mustermann'}
{'day': '2015-09-22', 'first_name': 'Albert', 'last_name': 'Grimaldi'}
{'day': '2015-09-22', 'first_name': 'Max', 'last_name': 'Mustermann'}

【讨论】：