PHP：基于数组拆分字符串

Question

以下是我要解析的数据：

50‐59 1High300.00 Avg300.00
90‐99 11High222.00 Avg188.73
120‐1293High204.00 Avg169.33

第一部分是权重范围，接下来是计数，接着是Highprice，以Avgprice结束>.

例如，我需要将上面的数据解析成一个数组，看起来像

[0]50-59
[1]1
[2]High300.00
[3]Avg300.00

[0]90-99
[1]11
[2]High222.00
[3]Avg188.73

[0]120‐129
[1]3
[2]High204.00
[3]Avg169.33

我想过创建一个可能的权重范围的数组，但我不知道如何使用数组的值来拆分字符串。

$arr = array("10-19","20-29","30-39","40-49","50-59","60-69","70-79","80-89","90-99","100-109","110-119","120-129","130-139","140-149","150-159","160-169","170-179","180-189","190-199","200-209","210-219","220-229","230-239","240-249","250-259","260-269","270-279","280-289","290-299","300-309");

任何想法将不胜感激。

Answer 1

让我们来解决这个看似废弃的问题：

这是您可以信任的模式 (Pattern Demo)：

^((\d{0,2})0\‐(?:\2)9) ?(\d{1,3})High(\d{1,3}\.\d{2}) ?Avg(\d{1,3}\.\d{2})

其他答案忽略了weight range 子字符串中的数字模式。范围起始整数始终以0 结尾，范围结束整数始终以9 结尾；范围总是跨越十个整数。

我的模式将捕获起始整数中0 之前的数字，并在短划线后立即引用它们，然后要求捕获的数字后跟9。

我想指出您的示例输入有点棘手，因为您的‐ 不是标准的-，它位于我键盘上的0 和= 之间。这是我要解决的一个偷偷摸摸的小问题。

方法（Demo）：

$keys=['weight range','count','Highprice','Avgprice'];
$in='50‐59 1High300.00 Avg300.00
90‐99 11High222.00Avg188.73
120‐1293High204.00 Avg169.33';

$out=preg_match_all('/((\d{0,2})0\‐(?:\2)9) ?(\d{1,3})High(\d{1,3}\.\d{2}) ?Avg(\d{1,3}\.\d{2})/',$in,$out)?array_diff_key($out,[0=>'',2=>'']):[];
// array_diff_key removes unwanted matching subarrays
foreach($out as $i=>$v){
    $result[]=array_combine($keys,array_column($out,0));
}
var_export($result);

输出：

array (
  0 => 
  array (
    'weight range' => '50‐59',
    'count' => '1',
    'Highprice' => '300.00',
    'Avgprice' => '300.00',
  ),
  1 => 
  array (
    'weight range' => '50‐59',
    'count' => '1',
    'Highprice' => '300.00',
    'Avgprice' => '300.00',
  ),
  2 => 
  array (
    'weight range' => '50‐59',
    'count' => '1',
    'Highprice' => '300.00',
    'Avgprice' => '300.00',
  ),
  3 => 
  array (
    'weight range' => '50‐59',
    'count' => '1',
    'Highprice' => '300.00',
    'Avgprice' => '300.00',
  ),
)

Answer 2

$arr = array('50-59 1High300.00 Avg300.00', 
             '90-99 11High222.00 Avg188.73', 
             '120-129 3High204.00 Avg169.33');

foreach($arr as $str) {
    if (preg_match('/^(\d+-\d{1,3})\s*(\d+)(High\d+\.\d\d) (Avg\d+\.\d\d)/i', $str, $m)) {
        array_shift($m); //remove group 0 (ie. the whole match)
        $result[] = $m;
    }
}
print_r($result);

输出：

Array
(
    [0] => Array
        (
            [0] => 50-59
            [1] => 1
            [2] => High300.00
            [3] => Avg300.00
        )

    [1] => Array
        (
            [0] => 90-99
            [1] => 11
            [2] => High222.00
            [3] => Avg188.73
        )

    [2] => Array
        (
            [0] => 120-129
            [1] => 3
            [2] => High204.00
            [3] => Avg169.33
        )

)

说明：

/                   : regex delimiter
    ^               : begining of string
    (               : start group 1
      \d+-\d{1,3}   : 1 or more digits a dash and 1 upto 3 digits ie. weight range
    )               : end group 1
    \s*             : 0 or more space character
    (\d+)           : group 2 ie. count
    (High\d+\.\d\d) : group 3 literal High followed by price
    (Avg\d+\.\d\d)  : Group 4 literal Avg followed by price
/i                  : regex delimiter and case Insensitive modifier.

为了更通用，您可以将 High 和 Avg 替换为 [a-z]+

Answer 3

'#^([\d]+\-[\d]+) ([\d]+)([a-zA-Z]+[\d\.]+) ([a-zA-Z]+[\d\.]+)#'

我认为这行不通，因为您在正则表达式中有空间 在重量和计数之间。我正在挣扎的事情是一排 像这样没有空间的地方。 120‐1293High204.00 Avg169.33那个 需要像[0]120‐129 [1]3 [2]High204.00 [3]Avg169.33一样解析

你是对的。这可以通过将重量位数限制为三个并使空格可选来解决。

'#^(\d+-\d{1,3}) *…

Answer 4

希望这会奏效：

    $string='50-59 1High300.00 Avg300.00
    90-99 11High222.00 Avg188.73
    120-129 3High204.00 Avg169.33';

    $requiredData=array();
    $dataArray=explode("\n",$string);
    $counter=0;
    foreach($dataArray as $data)
    {
        if(preg_match('#^([\d]+\-[\d]+) ([\d]+)([a-zA-Z]+[\d\.]+) ([a-zA-Z]+[\d\.]+)#', $data,$matches))    
        {
            $requiredData[$counter][]=$matches[1];
            $requiredData[$counter][]=$matches[2];
            $requiredData[$counter][]=$matches[3];
            $requiredData[$counter][]=$matches[4];
            $counter++;
        }
    }
    print_r($requiredData);