【发布时间】:2020-10-18 06:16:10
【问题描述】:
我是php新手
我有这个代码
$query = $request->all();
$allParameters = $request->all();
$keyword = 'جورج';
$apikey = 'XXX';
$googleApiUrl = 'https://www.googleapis.com/youtube/v3/search?part=snippet&q=' . $keyword . '&maxResults=' . 100 . '&key=' . $apikey;
// dd($googleApiUrl);
$ch = curl_init();
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_URL, $googleApiUrl);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, 1);
curl_setopt($ch, CURLOPT_VERBOSE, 0);
curl_setopt($ch, CURLOPT_SSL_VERIFYPEER, false);
$response = curl_exec($ch);
curl_close($ch);
$data = json_decode($response);
$value = json_decode(json_encode($data), true);
$init = new stdClass;
$array = [];
//dd($data->items);
foreach($data->items as $i => $item) {
$i++;
$init = new stdClass;
//dd($item->id->videoId);
//dd(sprintf("https://www.youtube.com/watch?v=%s",$item->id->videoId));
$ura = sprintf("https://www.youtube.com/watch?v=%s",$item->id->videoId);
$init->Nmae = $item->snippet->title;
// $init->url = sprintf("https://www.youtube.com/watch?v=%s",$item->id->videoId);
$init->Id = $i;
array_push($array,$init);
DB::table('wassoufs')->insert(
['Id' =>$i , 'Name' => $item->snippet->title, 'url'=> $ura]
);
};
未定义属性:stdClass::$videoId
dd(sprintf("https://www.youtube.com/watch?v=%s",$item->id->videoId));
工作正常
但是当我这样做时
$ura = sprintf("https://www.youtube.com/watch?v=%s",$item->id->videoId);
我得到未定义的属性:stdClass::$videoId
有什么原因吗?
【问题讨论】:
标签: php youtube-api