【发布时间】:2019-03-24 10:38:15
【问题描述】:
我正在使用以下解决方案将 Youtube 视频用作网站 div 背景:https://stackoverflow.com/a/45377998
可以在https://jsfiddle.net/350D/uq1vvavf/找到一个JSFiddle示例
我目前遇到的问题是并非所有视频都会显示。例如,JSFiddle 中的视频可以正常工作 (https://www.youtube.com/watch?v=R3AKlscrjmQ)。但是,例如,此视频将无法播放:https://www.youtube.com/watch?v=V5YOhcAof8I
我怀疑这可能与信号格式(720p、360p 等)有关。我尝试调试问题,发现流数组中仍然返回了非工作 Youtube 视频的链接(就像工作视频一样)。我感谢任何解决问题的提示。
HTML:
<video loop muted autoplay playsinline id="video"></video>
<pre></pre>
JS:
var vid = "R3AKlscrjmQ",
streams,
video_focused = true,
video_tag = $("#video"),
video_obj = video_tag.get(0);
$.getJSON("https://query.yahooapis.com/v1/public/yql", {
q: "select * from csv where url='https://www.youtube.com/get_video_info?video_id=" + vid + "'",
format: "json"
}, function(data) {
if (data.query.results && !data.query.results.row.length) {
streams = parse_youtube_meta(data.query.results.row.col0);
video_tag.attr({
src: streams['1080p'] || streams['720p'] || streams['360p']
});
document.addEventListener("visibilitychange", function() {
video_focused = !video_focused ? video_obj.play() : video_obj.pause();
});
} else {
$('pre').text('YQL request error...');
}
});
function parse_youtube_meta(rawdata) {
var data = parse_str(rawdata),
streams = (data.url_encoded_fmt_stream_map + ',' + data.adaptive_fmts).split(','),
result = {};
$.each(streams, function(n, s) {
var stream = parse_str(s),
itag = stream.itag * 1,
quality = false,
itag_map = {
18: '360p',
22: '720p',
37: '1080p',
38: '3072p',
82: '360p3d',
83: '480p3d',
84: '720p3d',
85: '1080p3d',
133: '240pna',
134: '360pna',
135: '480pna',
136: '720pna',
137: '1080pna',
264: '1440pna',
298: '720p60',
299: '1080p60na',
160: '144pna',
139: "48kbps",
140: "128kbps",
141: "256kbps"
};
//if (stream.type.indexOf('o/mp4') > 0) console.log(stream);
if (itag_map[itag]) result[itag_map[itag]] = stream.url;
});
return result;
};
function parse_str(str) {
return str.split('&').reduce(function(params, param) {
var paramSplit = param.split('=').map(function(value) {
return decodeURIComponent(value.replace('+', ' '));
});
params[paramSplit[0]] = paramSplit[1];
return params;
}, {});
}
【问题讨论】:
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几周以来我遇到了同样的问题......现在也找不到解决方案:(
标签: javascript html css youtube youtube-api