PHP在没有xpath的foreach循环中取消设置对象数组元素

Question

我需要取消设置对象中的所有payment 元素，以便仅显示以johndoe 作为收款人的支付元素。

代码部分工作。它只取消设置第一个支付元素。

xpath 适用于本示例，但不适用于我的实际项目。那么，除了取消设置 Payee 节点中所有没有 johndoe 的支付元素之外，还有什么替代方法？

对象：

$data = '
<root>
  <orderArray>
    <order>
      <Payments>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">a_test_user</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">johndoe</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">c_test_user</Payee>
        </Payment>
      </Payments>
    </order>
  </orderArray>
  <orderArray>
    <order>
      <Payments>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">d_test_user</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">johndoe</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">f_test_user</Payee>
        </Payment>
      </Payments>
    </order>
    <order>
      <Payments>
        <Payment>
          <PaymentStatus>failed</PaymentStatus>
          <Payee type="User">g_test_user</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">johndoe</Payee>
        </Payment>
        <Payment>
          <PaymentStatus>Succeeded</PaymentStatus>
          <Payee type="User">i_test_user</Payee>
        </Payment>
      </Payments>
    </order>
  </orderArray>
</root>
';

代码：

$xml = simplexml_load_string($data);

$sellerID = 'johndoe';

foreach($xml->orderArray as $order) {

    foreach($order->order as $val) {

        foreach ( $val->Payments->Payment as $payment )   {

            if($payment->Payee != $sellerID) {

                unset($payment[0]);

            }
        }

        $asxml .= $val->asXML();

    }
}


$xml = new DomDocument('1.0', 'utf-8');
$xml->loadXML('<Root>' . $asxml . '</Root>');

header('content-type: text/xml');
echo $xml->saveXML();

Answer 1

经过大量实验后，这首先会创建一个您要删除的付款列表，然后将其删除。这停止了​​操作您当前迭代的数据的问题。

同样在构建要删除的项目的循环中，它以相反的顺序构建列表，以便在尝试按位置删除内容时列表不会再次发生变化...

$asxml = "";
foreach($xml->orderArray as $order) {
    foreach($order->order as $val) {
        $i = 0;
        $removeList = [];
        foreach ( $val->Payments->Payment as $payment )   {
            if($payment->Payee != $sellerID) {
                array_unshift( $removeList, $i);
            }
            $i++;
        }
        foreach ( $removeList as $remove )  {
            unset($val->Payments->Payment[$remove]);
        }
    }
    $asxml.= $order->order->asXML();
}

$xml = new DomDocument('1.0', 'utf-8');
$xml->loadXML('<Root>' . $asxml . '</Root>');
$xml->formatOutput = true;

echo $xml->saveXML();