【发布时间】:2017-01-09 01:28:42
【问题描述】:
我正在尝试将函数的值分配给 DetailView 中的“值”。但是当我尝试时,我得到错误“类闭包的对象无法转换为字符串”
我尝试通过将函数的值也分配给另一个变量来返回函数的值,但仍然是同样的错误。
有人可以帮我弄清楚吗?
<?= DetailView::widget([
'model' => $model,
'attributes' => [
'Task_ID',
'Task_Title',
'Description',
'projects.project_name', //display project name instead of project id
// 'Assign_task_to',
//'tasksemp.Employee_ID',
[
'attribute' => 'Assign_task_to',
'format' => 'raw',
$data = function ($model) {
$assignEmpModel = Tasksemp::find()->where(['Task_ID' => $model->Task_ID])->all(); //get all the rows with teh same task_id
$employes = ''; //empty string
foreach ( $assignEmpModel as $employee ) {
$emp = Employee::find()->where(['Employee_ID'=>$employee->Employee_ID])->one(); //get all the employee_id
$name = $emp['employee_name']; //get the employee_name from the employees table
$employes .= ' '.$name.', '; //concatenate the names.
}
// return implode(', ',$employes);
//return $employes;
},
'value' => $data,
],
'start_date',
'due_date',
'priotiy_level',
'upload_documents',
],
]) ?>
我尝试将函数分配给变量 $data 但不起作用。
我也尝试将函数直接分配给该值,但同样的错误。
[
'attribute' => 'Assign_task_to',
'format' => 'raw',
'value' => function ($model) { //<----- ERROR HERE!
$assignEmpModel = Tasksemp::find()->where(['Task_ID' => $model->Task_ID])->all(); //get all the rows with teh same task_id
$employes = ''; //empty string
foreach ( $assignEmpModel as $employee ) {
$emp = Employee::find()->where(['Employee_ID'=>$employee->Employee_ID])->one(); //get all the employee_id
$name = $emp['employee_name']; //get the employee_name from the employees table
$employes .= ' '.$name.', '; //concatenate the names.
}
return $employes;
},
],
像这样尝试了 Bizley 的解决方案:
<?php $assignEmpModel = Tasksemp::find()->where(['Task_ID' => $model->Task_ID])->all(); //get all the rows with teh same task_id
$employes = ''; //empty string
foreach ( $assignEmpModel as $employee ) {
$emp = Employee::find()->where(['Employee_ID'=>$employee->Employee_ID])->one(); //get all the employee_id
$name = $emp['employee_name']; //get the employee_name from the employees table
$employes .= ' '.$name.', '; //concatenate the names.
?>
<?= DetailView::widget([
'model' => $model,
'attributes' => [
'Task_ID',
'Task_Title',
'Description',
'projects.project_name', //display project name instead of project id
// 'Assign_task_to',
//'tasksemp.Employee_ID',
[
'attribute' => 'Assign_task_to',
'format' => 'raw',
'value' => $employes,
],
'start_date',
'due_date',
'priotiy_level',
'upload_documents',
],
]) ?>
但现在错误提示文件意外结束。
【问题讨论】:
-
你不应该把这样的逻辑(使SQL查询填充
$employees变量)放在视图中,这是模型或单独组件的工作。 View 只负责显示和格式化。这违反了 MVC 原则。
标签: php yii2 yii2-advanced-app detailview