将总计添加到 bash 脚本的输出中

Question

我正在运行一个 bash 脚本，它查看错误日志并生成在 Mac 终端中打印的报告。

目前，输出如下所示：

This error report is derived from Command Logs from ________ to __________.

IP addresses:

109.xx.xxx.xxx

Error Codes List: 

(code 12)
(code 30)

Common Errors - Count: 

Code 2: 
Code 10: 
Code 11: 
Code 12: 237
Code 14: 
Code 20: 
Code 23: 
Code 30: 5
Code 35: 
Code 37: 
Code 52: 
/usr/local/bin/backerr: line 45: `$skipping': not a valid identifier
Total: 242

Total Files Transferred: 
3558

Count complete.

The following are details for each error:   
// all of the 242 above-referenced lines //

Skipped files: 
// lists all of the lines that have the word 'skipping\ ' //

如您所见，我没有正确的标识符：

    /usr/local/bin/backerr: line 45: `$skipping': not a valid identifier

这是我必须检测其中包含“skipping\”的行的代码，计算总数，并在上面的代码 XX: total 下打印总数。另外，我希望将“skipping\”总数添加到“Total：242”中。

  count=()
  total=0

  while read skipping; do
        (( count[$skipping]++, total++ ))      
  done < <(grep 'skipping\ ' $input_variable)

  for $skipping in $input_variable; do
    echo "Skipped: ${count[$skipping]}"
  done

“常见错误 - 计数：”部分的预期输出应如下所示：

    Common Errors - Count: 

    Code 2: 
    Code 10: 
    Code 11: 
    Code 12: 237
    Code 14: 
    Code 20: 
    Code 23: 
    Code 30: 5
    Code 35: 
    Code 37: 
    Code 52: 
    Skipped: 107 (I made up this number for this question)
    Total: 349

我被困在这里。请帮忙。

作为一种解决方法，而不是使用下面的代码：

      while read skipping; do
            (( count[$skipping]++, total++ ))      
      done < <(grep 'skipping\ ' $input_variable)

      for $skipping in $input_variable; do
        echo "Skipped: ${count[$skipping]}"
      done

我将其替换为：

  echo "Total Skipped Files: " ; egrep -c 'skipping' $input_variable ;

但是，这并没有真正产生我最初设想的理想结果。

Answer 1

您的 for 循环不应为索引变量使用美元符号：

for skipping in $input_variable; do
   ^^^