用完成的多个循环替换 for 循环中的部分字符串

Question

如何用我已经完成的循环次数来改变字符串的某个部分？

我正在使用 Chromedriver (find_element_by_xpath) 从网站上抓取数据。我看到当 for 循环计数超过 10 时会出现问题。 在 count 达到 10 之前，它已经能够将 /tr[1] 替换为 /tr[2] 等等，但是一旦出现两位数，事情就会变得复杂。

count = 0
for i in range(0, 21):
    count += 1
    string[65] = str(count)
    string = ''.join(string)
    print(string)
    string = list(string)

The output is:
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[2]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[3]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[4]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[5]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[6]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[7]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[8]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[9]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[10]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[110]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1210]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[13210]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[143210]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1543210]/td[2]


And what I expect output to be is:
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[2]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[3]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[4]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[5]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[6]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[7]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[8]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[9]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[10]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[11]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[12]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[13]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[14]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[15]/td[2]

Answer 1

试试这个：

string = "//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1]/td[2]"
all_list = [string[:65]+str(i+1)+string[66:] for i in range(0,15)]
print(*all_list, sep='\n')

输出：

//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[1]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[2]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[3]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[4]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[5]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[6]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[7]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[8]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[9]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[10]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[11]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[12]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[13]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[14]/td[2]
//*[@id='teams_wrapper']/div[2]/div[3]/div[2]/div/table/tbody/tr[15]/td[2]