如果两个值匹配，则合并/修改 PHP 数组答案

【问题标题】：Combine/modify PHP arrays if two values match如果两个值匹配，则合并/修改 PHP 数组
【发布时间】：2016-07-08 10:23:04
【问题描述】：

如果两个键相互匹配，我正在尝试合并两个数组并在数组中减去一个值。

这是我迄今为止编写的代码。

$dat = array();
for ($i = 0; $i <= (count($cashdrawer_sales) - 1); $i++) {
$obj = $cashdrawer_sales[$i];
foreach ($cashdrawer_refund as $k=>$ref) {
    if ($obj['cash_drawer']==$ref['cash_drawer'] && $ref['department_id']==$obj['department_id']) {
        $cash_drawer_total = $obj['cash_drawer_sale_total'] - $ref['cash_drawer_refund_total'];
        $arr = array('department_id'=>$obj['department_id'], 'cash_drawer' => $obj['cash_drawer'], 'cash_drawer_total' => $cash_drawer_total);
        array_push($dat,$arr);
    } else {
        $cash_drawer_total = $obj['cash_drawer_sale_total'];
        //  echo $cash_drawer_total."<br>";
        $arr = array('department_id'=>$obj['department_id'], 'cash_drawer' => $obj['cash_drawer'], 'cash_drawer_total' => $cash_drawer_total);
        array_push($dat,$arr);
    }
}
}
print_r($dat);

这是我想要操作的 $cashdrawer_sales 和 $cashdrawer_refund 数组的示例。

cashdrawer_sales

Array
(
[0] => Array
    (
        [department_id] => 80000
        [cash_drawer] => 21112
        [cash_drawer_sale_total] => 64.00
    )

[1] => Array
    (
        [department_id] => 80000
        [cash_drawer] => 21117
        [cash_drawer_sale_total] => 15.00
    )

[2] => Array
    (
        [department_id] => 80000
        [cash_drawer] => No Cash Drawer
        [cash_drawer_sale_total] => 50.00
    )

[3] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21112
        [cash_drawer_sale_total] => 193.00
    )

[4] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21113
        [cash_drawer_sale_total] => 30.00
    )

[5] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21117
        [cash_drawer_sale_total] => 10.00
    )

[6] => Array
    (
        [department_id] => 50502
        [cash_drawer] => No Cash Drawer
        [cash_drawer_sale_total] => 80.00
    )

[7] => Array
    (
        [department_id] => No Department
        [cash_drawer] => 21112
        [cash_drawer_sale_total] => 50.00
    )

[8] => Array
    (
        [department_id] => No Department
        [cash_drawer] => No Cash Drawer
        [cash_drawer_sale_total] => 125.00
    )

)

cashdrawer_refund

Array
(
[0] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21112
        [cash_drawer_refund_total] => 103.00
    )

[1] => Array
    (
        [department_id] => No Department
        [cash_drawer] => No Cash Drawer
        [cash_drawer_refund_total] => 25.37
    )
)

我觉得我真的很接近解决方案，但我无法正确解决

当我运行此代码时，每个原始值都会得到两个金额。所以（据我所知）我正在满足我多次通过的条件。

我假设这种情况正在发生，因为我对每次销售进行了两次迭代以分析退款。但是，我不确定该怎么做。

这是我的终极目标：

Array
(
[0] => Array
    (
        [department_id] => 80000
        [cash_drawer] => 21112
        [cash_drawer_total] => 64.00
    )

[1] => Array
    (
        [department_id] => 80000
        [cash_drawer] => 21117
        [cash_drawer_total] => 15.00
    )


[2] => Array
    (
        [department_id] => 80000
        [cash_drawer] => No Cash Drawer
        [cash_drawer_total] => 50.00
    )


[3] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21112
        [cash_drawer_total] => 90
    )


[4] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21113
        [cash_drawer_total] => 30.00
    )


[5] => Array
    (
        [department_id] => 50502
        [cash_drawer] => 21117
        [cash_drawer_total] => 10.00
    )

[6] => Array
    (
        [department_id] => 50502
        [cash_drawer] => No Cash Drawer
        [cash_drawer_total] => 80.00
    )


[7] => Array
    (
        [department_id] => No Department
        [cash_drawer] => 21112
        [cash_drawer_total] => 50.00
    )

[8] => Array
    (
        [department_id] => No Department
        [cash_drawer] => No Cash Drawer
        [cash_drawer_total] => 99.63
    )
)

有什么建议吗？

【问题讨论】：

你想为每个cash_drawer分开销售和退款吗？
我想从相应的销售总额中减去退款总额，并有一个包含新总额的新数组。
好的，但是您是否尝试为每个 cash_drawer 执行此工作？因为您的销售数组有 7 个元素，而您的退款数组有 2 个元素。
是的，我正在尝试按 department_id 为每个现金抽屉执行此操作（cash_drawer 不是唯一的，deptartment_id 是）。
这个想法是销售总额可能没有退款，但如果确实有退款，我需要从相应的总额中减去它并创建我的新数组。

标签： php arrays for-loop multidimensional-array

【解决方案1】：

使用department_id 和cash_drawer 的组合来创建结果键：

$result = array();

foreach( $cashdrawer_sales as $row )
{
    $key = $row['department_id'].'|'.$row['cash_drawer'];                      # <------
    if( !isset( $result[$key] ) )
    {
        $result[$key] = $row;
        unset( $result[$key]['cash_drawer_sale_total'] );
        $result[$key]['cash_drawer_total'] = 0;
    }
    $result[$key]['cash_drawer_total'] += $row['cash_drawer_sale_total'];
}

foreach( $cashdrawer_refund as $row )
{
    $key = $row['department_id'].'|'.$row['cash_drawer'];                      # <------
    if( !isset( $result[$key] ) )
    {
        $result[$key] = $row;
        unset( $result[$key]['cash_drawer_refund_total'] );
        $result[$key]['cash_drawer_total'] = 0;
    }
    $result[$key]['cash_drawer_total'] -= $row['cash_drawer_refund_total'];
}

然后使用array_values()删除键：

$result = array_values($result);

现在是$result：

Array
(
    [0] => Array
        (
            [department_id] => 80000
            [cash_drawer] => 21112
            [cash_drawer_total] => 64
        )

    [1] => Array
        (
            [department_id] => 80000
            [cash_drawer] => 21117
            [cash_drawer_total] => 15
        )

    [2] => Array
        (
            [department_id] => 80000
            [cash_drawer] => No Cash Drawer
            [cash_drawer_total] => 50
        )

    [3] => Array
        (
            [department_id] => 50502
            [cash_drawer] => 21112
            [cash_drawer_total] => 90
        )

    [4] => Array
        (
            [department_id] => 50502
            [cash_drawer] => 21113
            [cash_drawer_total] => 30
        )

    [5] => Array
        (
            [department_id] => 50502
            [cash_drawer] => 21117
            [cash_drawer_total] => 10
        )

    [6] => Array
        (
            [department_id] => 50502
            [cash_drawer] => No Cash Drawer
            [cash_drawer_total] => 80
        )

    [7] => Array
        (
            [department_id] => No Department
            [cash_drawer] => 21112
            [cash_drawer_total] => 50
        )

    [8] => Array
        (
            [department_id] => No Department
            [cash_drawer] => No Cash Drawer
            [cash_drawer_total] => 99.63
        )

)

【讨论】：

谢谢你。这是一个我自己不会想到的解决方案，而且比我尝试的更合乎逻辑。

【解决方案2】：

我对您的代码进行了一些更改，我想我已经找到了您想要的东西...

$dat = array();
for ($i = 0; $i < (count($cashdrawer_sales)); $i++) {
    $obj = $cashdrawer_sales[$i];
    foreach ($cashdrawer_refund as $k=>$ref) {
        if ($obj['cash_drawer']==$ref['cash_drawer'] && $ref['department_id']==$obj['department_id']) {
            $cash_drawer_total = $obj['cash_drawer_sale_total'] - $ref['cash_drawer_refund_total'];
            $arr = array('department_id'=>$obj['department_id'], 'cash_drawer' => $obj['cash_drawer'], 'cash_drawer_total' => $cash_drawer_total);
            $dat[] = $arr;
        } else {
            if (!in_array($obj, $dat)) {  // <-- check the array for the item, if it's not there then add it
                $dat[] = $obj;
            }
        }
    }
}

foreach($dat as $test){
    print_r($test);
    echo "<br>";
}

基本上，在将当前项添加回数组之前，我会检查它是否已经存在。

【讨论】：

【解决方案3】：

$dat = array();
for ($i = 0; $i <= (count($cashdrawer_sales) - 1); $i++) {


    $obj = $cashdrawer_sales[$i];
    $match=false; // assume initially that this $obj does not match any $ref till now
    foreach ($cashdrawer_refund as $k=>$ref) {
    //check if this ref matches if yes then break//you are for all obj each time it mathches as well as not matches an obj
         if ($obj['cash_drawer']==$ref['cash_drawer'] && $ref['department_id']==$obj['department_id']) {
              $match=true;
              break;    
         } 
     }
     // this accounts for one obj only once in your output
     if($match){
         $cash_drawer_total = $obj['cash_drawer_sale_total'] - $ref['cash_drawer_refund_total'];
         $arr = array('department_id'=>$obj['department_id'], 'cash_drawer' => $obj['cash_drawer'], 'cash_drawer_total' => $cash_drawer_total);
         array_push($dat,$arr);
     }else{
         $cash_drawer_total = $obj['cash_drawer_sale_total'];
             //  echo $cash_drawer_total."<br>";
         $arr = array('department_id'=>$obj['department_id'], 'cash_drawer' => $obj['cash_drawer'], 'cash_drawer_total' => $cash_drawer_total);
         array_push($dat,$arr);
     }
}
print_r($dat);

【讨论】：

我还要补充一点，这不是最快的方法。您可以对数组 1 和数组 2 进行排序，然后使用更好的检查在 O(n logn) 而不是 O(n^2) 中完成此操作

【解决方案4】：

要解决这样的问题，最好的方法是在你的脑海中或在论文中解决它然后实施它。

据我了解，您想为有退款的人修改销售总额。然后你需要检查你所有的销售额：

foreach ($cashdrawer_sales as $sale_key => $sale) {
}

然后我们想检查这个部门的现金抽屉是否有退款。我们检查所有退款：

foreach ($cashdrawer_sales as $sale_key => $sale) {
    foreach ($cashdrawer_refund as $refund_key => $refund) {
        if ($sale['cash_drawer'] === $refund['cash_drawer'] && 
                $sale['department_id'] === $refund['department_id']) {
            // and if there was refund then we need to subtract it:
            $cashdrawer_sales[$sale_key]['new_total'] = $sale['cash_drawer_sale_total'] -
                    $refund['cash_drawer_refund_total'];
        }
    }
}

这应该可以完成工作。不是说要在同一个数组中提交更改，我使用了密钥($cashdrawer_sales[$sale_key]['new_total'])。

希望对您有所帮助。

【讨论】：