在 for 循环中将两个条目粘在一起答案

【问题标题】：Sticking together double entries in a for loop在 for 循环中将两个条目粘在一起
【发布时间】：2013-03-22 05:11:10
【问题描述】：

我有一个来自 JSON 页面的回合和团队列表......

目前，我正在回应如上所示，但我希望任何双轮比赛都将两支球队一起展示，而不是分开展示。

这是我要展示的示例...

这是我现在正在使用的......我不知道如何解决它。

//get the page 
$str = file_get_contents('http://fantasy.mlssoccer.com/web/api/elements/498/');
$jsonarray = json_decode($str, true);

//count how many entries
$howmanyrounds = count($jsonarray['fixtures']['all']);

//for each entry
for($whichround = 0; $whichround < $howmanyrounds; $whichround++)
{
    //this returns a value like 'Round 6'
    $gameweek = $jsonarray['fixtures']['all'][$whichround][1];
    //Cut out just the number
    $roundno = intval(substr($gameweek, -(strlen($gameweek)-6)));

    //this returns a value like 'Chivas USA (H)'
    $opponents = $jsonarray['fixtures']['all'][$whichround][2];
    //This cuts out the actual team name
    $team = substr($opponents, 0, (strlen($opponents)-4));

    echo $roundno." ".$team."<br>";
}

我尝试了几种不同的方法，但最终都无法达到我想要的效果。这应该很容易。知道怎么做吗？

【问题讨论】：

substr($gameweek, -(strlen($gameweek)-6)) == substr($gameweek, 6) :)
谢谢。我的方法也有效，但我猜有点奇怪和过于复杂。

标签： php json for-loop

【解决方案1】：

您可以使用中间数组根据轮数将团队分组：

$rounds = array();

for($whichround = 0; $whichround < $howmanyrounds; $whichround++)
{
    // ...
    $rounds[$roundno][] = $team;
}

foreach ($rounds as $roundno => $teams) {
    echo $roundno . " " . join(' & ', $teams)."<br>";
}

【讨论】：

【解决方案2】：

尝试将值加入索引数组：

$arrJoined = array();

for($whichround = 0; $whichround < $howmanyrounds; $whichround++)
{
    //this returns a value like 'Round 6'
    $gameweek = $jsonarray['fixtures']['all'][$whichround][1];
    //Cut out just the number
    $roundno = intval(substr($gameweek, -(strlen($gameweek)-6)));

    //this returns a value like 'Chivas USA (H)'
    $opponents = $jsonarray['fixtures']['all'][$whichround][2];
    //This cuts out the actual team name
    $team = substr($opponents, 0, (strlen($opponents)-4));

    $arrJoined[$roundno] = ($arrJoined[$roundno] == null ? $team : $arrJoined[$roundno].' & '.$team);
}

然后只输出你的 $arrJoined 的内容。

【讨论】：

谢谢.. 这似乎有效，但现在我需要让它忽略从 $arrJoined[1] 到 $arrJoined[5] 的所有空白数组条目。我应该能够做到（我认为） - 谢谢！
没问题！也没有空白数组条目，请尝试 print_r($arrJoined); :)
哦..是的，我把它弄糊涂了。我的意思是，在这种情况下，数字从 6 开始，并且会根据运行的周数而有所不同，所以我需要解决它，但这也应该是可以管理的。
啊，是的 - 只需使用 foreach 循环 $arrJoined 而不是常规的 for 循环。您还可以使用我提供的方法在数组中免费排序。

【解决方案3】：

用它作为中间数组，你应该很好

$str = file_get_contents('http://fantasy.mlssoccer.com/web/api/elements/498/');
            $array = json_decode($str, true);
            $temp = $array['fixtures']['all'];
            $req_array = array();
            foreach($temp as $value)
            {
                list($dummy, $round)  = explode(" ", $value[1]);
                           $value[2] = str_replace('-','',$value[2]);
                if(isset($req_array["Round $round"]) 
                   && ($req_array["Round $round"] != '') 
                   )
                {
                    $req_array["Round $round"] = $req_array["Round $round"]."&".$value[2];
                }
                else if($value[2] != '-')
                {
                    $req_array["Round $round"] = $value[2];
                }
            }

输出来自$req_array

  Array
   (
    [Round 6] => D.C. United (H)
[Round 7] => 
[Round 8] => New York Red Bulls (A)&Los Angeles Galaxy (A)
[Round 9] => Portland Timbers (H)
[Round 10] => Chivas USA (H)
[Round 11] => Seattle Sounders FC (H)&Houston Dynamo (A)
[Round 12] => D.C. United (A)
 ---
)

【讨论】：

【解决方案4】：

我的建议是，您只需编写另一个数组 (targetAray)，然后将数据推送到该数组中，然后打印该数组，如下所示：

$targetArray = array();   //additional array to store values
//count how many entries
$howmanyrounds = count($jsonarray['fixtures']['all']);

//for each entry
for($whichround = 0; $whichround < $howmanyrounds; $whichround++)
{
    //this returns a value like 'Round 6'
    $gameweek = $jsonarray['fixtures']['all'][$whichround][1];

    //Cut out just the number
    $roundno = intval(substr($gameweek, -(strlen($gameweek)-6)));

    //this returns a value like 'Chivas USA (H)'
    $opponents = $jsonarray['fixtures']['all'][$whichround][2];
    //This cuts out the actual team name
    $team = substr($opponents, 0, (strlen($opponents)-4));

   //below code you need to add. 
   if(array_key_exists($roundno, $targetArray))
     $targetArray[$roundno] = $targetArray[$roundno]. "&" .$team;
   else
    $targetArray[$roundno] = $team;
    echo $roundno." ".$team."<br>";
}
//this will give you your data
print_r($targetArray);

【讨论】：