未找到任何参数的“projeto”反向。尝试了 1 种模式：['delete/(?P<pk>[0-9]+)/projeto/$']

Question

向开发者致敬。我有一个应用程序，在索引中我使用表字段之间的 ForeignKey 调用一些查询，使用 User 作为参数。这些视图适用于没有 ForeignKey 的其他表。但是当我调用请求数据库的 CRUD（删除、更新、创建）函数时，它会返回一个错误：

Request Method: GET
Request URL:    http://127.0.0.1:8000/delete/13/
Django Version: 3.2
Exception Type: NoReverseMatch
Exception Value:    
Reverse for 'projeto' with no arguments not found. 1 pattern(s) tried: ['delete/(?P<pk>[0-9]+)/projeto/$']
Exception Location: C:\webcq\venv\lib\site-packages\django\urls\resolvers.py, line 694, in _reverse_with_prefix
Python Executable:  C:\webcq\venv\Scripts\python.exe
Python Version: 3.8.6
Python Path:    
['C:\\webcq',

 'C:\\webcq\\venv',
 'C:\\webcq\\venv\\lib\\site-packages']
Server time:    Thu, 20 May 2021 21:03:07 +0000

url.py 项目

from django.contrib import admin
from django.urls import include, path


urlpatterns = [


    path('admin/', admin.site.urls),
    path('', include('imagem.urls', namespace='home')),
    path('view/<int:pk>/', include('imagem.urls', namespace='view')),
    path('edit/<int:pk>/', include('imagem.urls', namespace='edit')),
    path('update/<int:pk>/', include('imagem.urls', namespace='update')),
    path('delete/<int:pk>/', include('imagem.urls', namespace='delete')),


]

urls.py 应用程序

from django.urls import path
from . import views

app_name = 'imagem'

urlpatterns = [

    path('', views.home, name='home'),
    path('projeto/', views.projeto, name='projeto'),
    path('form/', views.form, name='form'),
    path('create/', views.create, name='create'),
    path('view/<int:pk>/', views.view, name='view'),
    path('edit/<int:pk>/', views.edit, name='edit'),
    path('update/<int:pk>/', views.update, name='update'),
    path('delete/<int:pk>/', views.delete, name='delete'),

]

views.py 应用程序

视图工作，但不重定向到视图名称并返回上述错误。

def edit(request, pk):
    data = {}
    data['db'] = Projeto.objects.get(pk=pk)
    data['form'] = ProjetoForm(instance=data['db'])
    return render(request, 'imagem/form.html', data)

def update(request, pk):
    data = {}
    data['db'] = Projeto.objects.get(pk=pk)
    form = ProjetoForm(request.POST or None, instance=data['db'])
    if form.is_valid():
        form.save()
        return redirect('imagem:projeto')

def delete(request, pk):
    db = Projeto.objects.get(pk=pk)
    db.delete()
    return redirect('imagem:projeto')

form.html

          {% for dbs in db %}

            <td>
               <th>{{dbs.id}}</th>
                <td>{{dbs.nome}}</td>
                <td>{{dbs.tipo_img}}</td>
                <td>
                      <a href="/view/{{dbs.id}}/" class="btn btn-dark">Visualizar</a>
                      <a href="/edit/{{dbs.id}}/" class="btn btn-primary">Editar</a>
                      <a href="/delete/{{dbs.id}}/" class="btn btn-danger btnDel">Deletar</a>
                </td>
            </tr>
            {% endfor %}

models.py 应用程序

class Projeto(models.Model):
    tipo_img = models.ForeignKey(TipoImg, on_delete=models.CASCADE)
    nome = models.CharField(max_length=200)
    autor = models.ForeignKey(User, on_delete=models.CASCADE, default='1')

    def __str__(self):
        return self.nome

Answer 1

由于projeto 在imagem url 中，它是从urls.py 调用的，名称空间为“home”，我相信您想在视图中使用return redirect('home:projeto')（而不是“imagem:projeto”） )。

您可能还想从 url 中删除“视图”、“编辑”、“更新”和“删除”，因为您在 imagem 中也有（或从 imagem 中删除）。

您的第一个url.py 应该是：

from django.contrib import admin
from django.urls import include, path


urlpatterns = [
    path('admin/', admin.site.urls),
    path('', include('imagem.urls', namespace='home')),
 ] 

对于未来的自己，您可能希望将根 url 文件命名为 urls.py；其他urls.py 通常会存在于他们自己的应用文件夹中。

所以会产生这样的文件结构：

project_name/project_name/settings.py
project_name/project_name/urls.py
project_name/imagem/urls.py
project_name/imagem/views.py
project_name/imagem/models.py