Django - 如何在电子邮件中添加发件人名称？

Question

我想要实现的是让当前登录用户的发送者名称与关联名称显示在接收者收件箱中，如下所示：

'associaton-name'@domain.com

我已经在下面评论了它，我试图在views.py 中实现它

经过几天和几个小时的工作，似乎找不到任何相关的解决方案。

非常感谢您的帮助，伙计们！

Django：1.10
蟒蛇：3.6

---

views.py

class mailPost(FormView):
   success_url = '.'
   form_class = mailHandler
   template_name = 'post/post.html'

   def form_valid(self, form):
       messages.add_message(self.request, messages.SUCCESS, 'Email Sent!')
       return super(mailPost, self).form_valid(form)

   def form_invalid(self, form):
       messages.add_message(self.request, messages.WARNING,
                         'Email not sent. Please try again.')
       return super(mailPost, self).form_invalid(form)

   def post(self, request, *args, **kwargs):
       form_class = self.get_form_class()
       form = self.get_form(form_class)

       if form.is_valid():
           sender = "noreply@domain.com"      # Instead of noreply I wish for current requested associaton name
           receiver = form.cleaned_data.get('receiver')
           cc = form.cleaned_data.get('cc')
           bcc = form.cleaned_data.get('bcc')
           subject = form.cleaned_data.get('subject')
           message = form.cleaned_data.get('message')
           time = datetime.now()
           asoc_pk = Association.objects.filter(asoc_name=self.request.user.association)
           asoc = Association.objects.get(id=asoc_pk)

           Email.objects.create(
               sender=sender,
               receiver=receiver,
               cc=cc,
               bcc=bcc,
               subject=subject,
               message=message,
               association=asoc,
               sentTime=time
           )

           msg = EmailMultiAlternatives(subject, message, sender, [receiver], bcc=[bcc], cc=[cc])
           msg.send()

           return self.form_valid(form)
       else:
           return self.form_invalid(form)

---

models.py

class Email(models.Model):
   sender = models.CharField(max_length=254)
   sentTime = models.DateTimeField(auto_now_add=True, blank=False)
   subject = models.CharField(max_length=254)
   receiver = models.CharField(max_length=254)
   cc = models.CharField(max_length=254)
   bcc = models.CharField(max_length=254)
   message = models.TextField()
   association = models.ForeignKey(Association)

   class Meta:
       db_table = 'Email'    


class Association(models.Model):
    asoc_name = models.CharField(max_length=50, null=True, blank=True, unique=True)


   class Meta:
       db_table = 'Association'     


class Administrator(AbstractUser):
   ...
   association = models.ForeignKey(Association)


   class Meta:
       db_table = 'Administrator'

Answer 1

我不确定我是否正确理解了您的问题。您可以通过调用self.request.user 来访问经过身份验证的用户（假设您使用的是 Django 身份验证系统）。

您必须在Association 和用户之间建立关系：

class Association(models.Model):
    asoc_name = models.CharField(max_length=50, null=True, blank=True, unique=True)
    # Option 1 - if one user can be a member of several associations
    members = models.ManyToMany(User)

   class Meta:
       db_table = 'Association'

如果用户只能是一个关联的成员，则为新模型实例：

# Option 2
class Membership(Model):
    association = models.ForeignKey(Association)
    user = models.ForeignKey(User, unique=True)

您使用直接查找（或反向关系）获得关联。

 # option 1
 if form.is_valid():
       sender = Association.objects.filter(members=self.request.user).first()
       # sender might be None

 # option 2
 if form.is_valid():
       membership = Membership.objects.filter(user=self.request.user).first()
       if membership:
           sender = membership.association

https://docs.djangoproject.com/en/1.11/topics/db/examples/many_to_many/