从 cmd 调用时任务延迟不起作用答案

【问题标题】：Tasks delay not working when called from cmd从 cmd 调用时任务延迟不起作用
【发布时间】：2019-06-01 05:13:16
【问题描述】：

我在一个 cmd 和 shell 中运行 celery worker，我正在运行我的任务，但是当我像 TestTaskOne.delay() 这样调用我的任务时它不起作用，cmd 只是在那里暂停，我必须以 ctrl+c 和 worker 终止也没有得到任何任务。

发生这种情况的任何想法。

对于芹菜工人，我正在使用celery -A Project worker -l info -P eventlet

tasks.py

from __future__ import absolute_import, unicode_literals
from celery import task

@task
def TestTaskOne():
    msg = "DEFAULT   TASK   IS   WORKING......"
    return msg

celery.py

from __future__ import absolute_import, unicode_literals
import os, logging
from celery import Celery
from celery.schedules import crontab


# set the default Django settings module for the 'celery' program.
os.environ.setdefault('DJANGO_SETTINGS_MODULE', 'RestUserAPI.settings')

app = Celery('UserAPI')

# Using a string here means the worker don't have to serialize
# the configuration object to child processes.
# - namespace='CELERY' means all celery-related configuration keys
#   should have a `CELERY_` prefix.
app.config_from_object('django.conf:settings', namespace='CELERY')

# Load task modules from all registered Django app configs.
app.autodiscover_tasks()


@app.task(bind=True)
def debug_task(self):
    print('Request: {0!r}'.format(self.request))

settings.py

CELERY_BROKER_URL = 'mongodb://localhost:27017'
CELERY_RESULT_BACKEND = "mongodb"
CELERY_IGNORE_RESULT = False
CELERY_TRACK_STARTED = True
CELERY_MONGODB_SCHEDULER_DB = "celery"
CELERY_MONGODB_SCHEDULER_COLLECTION = "schedules"
CELERY_MONGODB_SCHEDULER_URL = "mongodb://localhost:27017"
CELERY_ACCEPT_CONTENT = ['application/json']
CELERY_TASK_SERIALIZER = 'json'
CELERY_RESULT_SERIALIZER = 'json'
CELERY_TIMEZONE = TIME_ZONE

【问题讨论】：

标签： django python-3.x celery celery-task

【解决方案1】：

我探索了 celery 文档，似乎我错过了在我的项目中添加 celery 应用程序__init__.py

添加这些行后，延迟功能起作用了。

__init__py

from __future__ import absolute_import, unicode_literals

# This will make sure the app is always imported when
# Django starts so that shared_task will use this app.
from .celery import app as celery_app

__all__ = ['celery_app']

【讨论】：