Django 模型自定义序列化为 JSON答案

【问题标题】：Django Model Customize Serialization to JSONDjango 模型自定义序列化为 JSON
【发布时间】：2014-10-05 01:16:12
【问题描述】：

默认序列化器实现：

class Serializer(base.Serializer):
    """
    Serializes a QuerySet to basic Python objects.
    """

    internal_use_only = True

    def start_serialization(self):
        self._current = None
        self.objects = []

    def end_serialization(self):
        pass

    def start_object(self, obj):
        self._current = {}

    def end_object(self, obj):
        self.objects.append({
            "model"  : smart_unicode(obj._meta),
            "pk"     : smart_unicode(obj._get_pk_val(), strings_only=True),
            "fields" : self._current
        })
        self._current = None

数据输出格式：

[{“pk”：2，“model”：“android.job”，“fields”：{“status”：“lol”，“customer”：“HAHA”}}，{“pk”：3 ，“模型”：“android.job”，“字段”：{“状态”：“lul”，“客户”：“BWAHA”}}]

我的覆盖：

class MySerialiser(Serializer):
    def start_serialization(self):
        self._current = None
        self.objects = []

    def end_serialization(self):
        pass

    def start_object(self, obj):
        self._current = {}

    def end_object(self, obj):
        self._current['id'] = obj._get_pk_val()
        self.objects.append(self._current)

输出格式：

{"status": "lol", "customer": "HAHA", id:2L}{"status": "lul", "customer": "BWAHA", id:3L}

我需要什么：

[{"status": "lol", "customer": "HAHA", id:2L}, {"status": "lul", "customer": "BWAHA", id:3L}]

注意 - 这是在 Django 中 - 所有这些都是字符串类型！不要假设它们是列表/字典

【问题讨论】：

看来你让这个过于复杂了。 See this question and answer

标签： python json django serialization

【解决方案1】：

终于成功了！

class MySerialiser(Serializer):
    def start_serialization(self):
        self._current = None
        self.objects = []

    def end_serialization(self):
        simplejson.dump(self.objects, self.stream, cls=DjangoJSONEncoder, **self.options)

    def getvalue(self):
        if callable(getattr(self.stream, 'getvalue', None)):
            return self.stream.getvalue()

    def start_object(self, obj):
        self._current = {}

    def end_object(self, obj):
        self._current['id'] = obj._get_pk_val()
        self.objects.append(self._current)
        self._current = None

【讨论】：