表单无效后未呈现 django 上下文表单答案

【问题标题】：django context form not rendered after form invalid表单无效后未呈现 django 上下文表单
【发布时间】：2015-02-01 20:29:04
【问题描述】：

我有一个医生详细信息视图，其中我已将表单作为上下文传递：

class HospitalDoctorDetailView(DetailView):
context = {}
model = HospitalDoctor
template_name = "hospital_doctor_detail.html"
context_object_name = 'doctor'

def get_context_data(self, **kwargs):
    context = super(HospitalDoctorDetailView, self).get_context_data(**kwargs)
    context['appointment_form'] = AppointmentForm1
    return context

我在名为hospital_doctor_detail.html的模板中使用了这个表单：

<form action="/appointment/{{doctor.id}}/{{doctor.hospital.id}}/" method="post">{% csrf_token %}
First Name:<br/>
{{ form.first_name.errors }}
{{ appointment_form.first_name }}<br/>
Middle Nmae:<br/>
{{ form.middle_name.errors }}
{{ appointment_form.middle_name }}<br/>
Last Name:<br/>
{{ form.last_name.errors }}
{{appointment_form.last_name}}<br/>
Age:<br/>
{{ form.age.errors }}
{{ appointment_form.age }}<br/>
Date:<br/>
{{ form.appointment_date.errors }}
{{ appointment_form.appointment_date }}<br/>
<br/>
<input type="submit" value="Take Appointment" style="background-color:#EFEFEF; border:1px solid #000;" />
</form>

我的表单 AppointmentForm1 是一个模型表单。要提交表单，我已经写了一个视图：

def TakeAppointmentView(request, pk, hpk):
doctor = HospitalDoctor.objects.get(pk=pk)
hospital = Hospital.objects.get(pk=hpk)
if request.method == "POST":
    form = AppointmentForm1(request.POST)
    if form.is_valid():
        app = DoctorAppointment()
        app.user = request.user
        app.doctor = doctor
        app.hospital = hospital
        app.first_name = form.cleaned_data['first_name']
        app.middle_name = form.cleaned_data['middle_name']
        app.last_name = form.cleaned_data['last_name']
        app.age = form.cleaned_data['age']
        app.appointment_date = form.cleaned_data['appointment_date']
        app.save()
        messages.success(request, "Thank you for taking appointment")
        return redirect("doctor_detail", pk)
        #return redirect("/home/")
    else:
        return render_to_response("hospital_doctor_detail.html", {"appointment_form":form}, context_instance=RequestContext(request))
else:
    form = AppointmentForm1()
return render_to_response("hospital_doctor_detail.html", {"appointment_form":form}, context_instance=RequestContext(request))

如果表格有效，预约成功，但如果表格无效，我想将其重定向到同一个医生详细信息视图。

这里我收到一个错误，如果表单无效，它会重定向到带有错误消息的医生详细信息视图，但表单不显示？这里有什么问题？？

【问题讨论】：

标签： python django forms templates view

【解决方案1】：

您将以{"application_form": form} 的身份将表单返回到您的模板。

您的模板对任何名为 form 的变量一无所知。

而不是使用：

{{ form.first_name.errors }}

尝试对每个错误消息使用以下内容：

{{ application_form.first_name.errors }}

【讨论】：