【发布时间】:2019-03-15 00:11:35
【问题描述】:
假设我有两个不同的应用程序:
teacher/models.py:
Teacher(models.Model):
name = models.CharField(max_length=300)
class/models.py:
Class(models.Model):
name = models.CharField(max_length=300)
teacher = models.ForeignKey(Teacher)
students = models.ManyToManyField(Student)
我想让所有的老师都有课程和所有的课程。
我想要的结果:
{[
teacher: '3L' #Teachers Id
classes: ['20L','14L','30L'] #list of Class objects or ids with the above teacher
],
[# similar to above]
}
这可能吗?这就是我目前正在做的事情:
classes = Class.objects.all()
teachers = Teacher.objects.filter(id__in=classes.value_list('teacher',flat=True).distinct())
for teacher in teachers:
classes_for_teachers = classes.objects.filter(teacher=teacher)
在上面的代码中,有四个使用循环进行的查询,这肯定会增加时间复杂度。有没有更好的解决方案?提前致谢。
【问题讨论】:
标签: python mysql django prefetch