使用 Django 和 jQuery 的订阅表单

Question

我一直在做这个页面，可以在其中订阅该站点，并且我一直在尝试在 Django 模板中使用 jQuery 触发表单。 现在，如果用户想订阅，注册页面会正确打开，如果一切正常，注册会顺利进行，然后会返回可以登录的主页；如果出现错误（错误的用户名或电子邮件或密码），它会返回主页而不指出任何错误 - 只有当您再次点击打开注册表时才会显示错误。

我将复制粘贴我的代码。

• 主页.html

	{% if user.is_authenticated %}
	<h2>Welcome back, {{ user.username }}. Let's explore the World together!</h2>
	{% else %}
	
  <!-- Trigger the modal with a button -->
  <h2><button id="myBtn">Subscribe now :)</a></h2>

  <!-- Modal -->
  <div class="modal fade" id="myModal" role="dialog">
    <div class="modal-dialog">
    
      <!-- Modal content-->
      <div class="modal-content">
        <div class="modal-header">
          <button type="button" class="close" data-dismiss="modal">&times;</button>
          <h3 class="modal-title">Register with Tent a garden</h3>
        </div>
        <div class="modal-body">
        {% if registered %}
        
			<h4>Tent a garden says: <strong>thank you for registering!</strong></h4>
			<a href="/">Return to the homepage.</a><br />
			{% else %}
			<h4>Tent a garden says: <strong>register here!</strong></h4><br />
			
			<form id="user_form" method="post" action="" enctype="multipart/form-data">
			
				{% csrf_token %}
				
				{{ user_form.as_p }}
				{{ profile_form.as_p }}
				
				<input type="submit" class="btn btn-info" name="submit" value="Register" />
			</form>
        {% endif %}
        </div>
        <div class="modal-footer">
			<button type="button" class="btn btn-default" data-dismiss="modal">Close</button>
        </div>
    
    </div>
    </div>
    </div>
    
    <script>
		$(document).ready(function(){
			$("#myBtn").click(function(){
				$("#myModal").modal();
			});
		});
	</script>
  
	<h2>Are you already a member? Then, <a href="/login/">login</a>!</h2>
	{% endif %}

• views.py

  from django.shortcuts import render_to_response, render, redirect
  from django.template import RequestContext
  from django.http import HttpResponseRedirect, HttpResponse
  from django.core.urlresolvers import reverse
  from django.contrib.auth import authenticate, login, logout
  from django.contrib.auth.decorators import login_required
  
  from tentagarden.forms import UserForm, UserProfileForm
  
  def home(request):
      context = RequestContext(request)
  
      registered = False
  
      if request.method == 'POST':
          user_form = UserForm(data=request.POST)
          profile_form = UserProfileForm(data=request.POST)
  
          if user_form.is_valid() and profile_form.is_valid():
              user = user_form.save()
  
              user.set_password(user.password)
              user.save()
  
              profile = profile_form.save(commit=False)
              profile.user = user
  
              if 'picture' in request.FILES:
                  profile.picture = request.FILES['picture']
  
              profile.save()
  
              registered = True
  
          else:
              print user_form.errors, profile_form.errors
  
      else:
          user_form = UserForm()
          profile_form = UserProfileForm()
  
      return render_to_response(
              'tentagarden/home.html',
              {'user_form': user_form, 'profile_form': profile_form, 'registered': registered},
              context)
  

• forms.py

  from django import forms
  from django.forms import ModelForm
  from tentagarden.models import UserProfile
  from django.contrib.auth.models import User
  
  class UserForm(forms.ModelForm):
      password = forms.CharField(widget=forms.PasswordInput())
  
      class Meta:
          model = User
          fields = ('username', 'email', 'password')
  
  class UserProfileForm(forms.ModelForm):
      class Meta:
          model = UserProfile
          fields = ('website', 'picture')
  

• models.py

  from django.db import models
  from django.utils import timezone
  from autoslug import AutoSlugField
  from django.contrib.auth.models import User
  
  class UserProfile(models.Model):
      user = models.OneToOneField(User)
      website = models.URLField(blank=True)
      picture = models.ImageField(upload_to='profile_images', blank=True)
  
      def __unicode__(self):
          return self.user.username
  

• urls.py

  from django.conf.urls import patterns, url
  
  urlpatterns = patterns('tentagarden.views',
      url(r'^$', 'home', name='home'),
      url(r'^list/$', 'list', name='list'),
      url(r'^login/$', 'user_login', name='login'),
      url(r'^logout/$', 'user_logout', name='logout'),
  )
  

我错过了什么？

谢谢！

Answer 1

您的表单错误未显示，因为该表单仅在用户单击按钮时显示。

<script>
    $(document).ready(function(){
        $("#myBtn").click(function(){
            // You need to be triggering this when there was an error
            $("#myModal").modal();
        });
    });
</script>

一个简单的补丁修复是将一个额外的上下文变量传递给模板。类似registration_failed = True 或False。

然后像这样修改你的代码：

# in views.py
else:
    print user_form.errors, profile_form.errors
    return render_to_response(
        'tentagarden/home.html',
        {'user_form': user_form, 'profile_form': profile_form, 'registered': registered, 'registration_failed': True},
        context)

还有：

<!-- in your HTML -->
<script>
    $(document).ready(function(){
        $("#myBtn").click(function(){
            $("#myModal").modal();
        });
        // If the template is rendered with registration_failed == true
        // Then send a click to the button controlling the modal.
        if ({{registration_failed}}) {
            $("#myBtn").click();
        }
    });
</script>

请注意，这不是解决您问题的最佳长期解决方案，我认为您需要大量重构代码。但这将解决眼前的问题。