【发布时间】:2015-04-10 01:33:53
【问题描述】:
我有用于显示弹出窗口的模态,当您单击发布按钮时,它会进行 ajax 函数调用,我也将其设置为模态切换,但它不会在提交时切换模态,而我没有不知道怎么解决。
div 类
<div class="modal fade bs-example-modal-sm2" tabindex="-1" role="dialog" aria-labelledby="mySmallModalLabel" aria-hidden="true" id='post_modal'>
<div class="modal-dialog modal-sm2">
<div class="modal-content">
{% if is_user_profile %}
<div id='make_post' styly='padding:7px;'>
<form method='POST'>
{% csrf_token %}
title: <input type ='text' id='post_title'><br>
post:<textarea id='post_text'></textarea><br>
<button id='makepost' type="button" class="btn btn-primary" data-dismiss="modal">Post</button>
{% for user in user_data %}
<input type='hidden' id='username' value='{{user.username}}' >
{%endfor%}
</form>
</div>
{%endif%}
</div>
</div>
</div>
ajax 调用
$("#makepost").click(function() {
var post_title = document.getElementById("post_title").value;
var post_text = document.getElementById("post_text").value;
var username = document.getElementById("username").value;
$.ajax({
url : "/makepost/",
type : "POST",
dataType: "json",
data : {
csrfmiddlewaretoken: '{{ csrf_token }}',
username: username,
post_title: post_title,
post_text: post_text,
},
success : function(json) {
document.getElementById('output').innerHTML = (json['message']);
updatePostSection(json['user_posts']);
},
error : function(xhr,errmsg,err) {
console.log(xhr.status + ": " + xhr.responseText);
document.getElementById('output').innerHTML = "Request Failed.";
}
});
return false;
});
【问题讨论】:
-
您的问题是发布后模式没有消失吗?还是我错过的另一件事?
标签: javascript jquery ajax django twitter-bootstrap