重复键值违反唯一约束“core_user_username_key”详细信息：键（用户名）=（）已存在

Question

美好的一天！创建了一个单独的页面来更改密码，当您输入密码并重复并单击“更改密码”按钮时，出现重复键值违反唯一约束“core_user_username_key”错误 详细信息：键（用户名）= 已存在 如何解决这个错误？

forms.py

class CallcenterPasswordChange(forms.ModelForm):
    password1 = forms.CharField(widget=forms.PasswordInput(),  label='Новый пароль')
    password2 = forms.CharField(widget=forms.PasswordInput(), label='Повтор нового пароля')

    def clean(self):
        password1 = self.cleaned_data.get("password1")
        password2 = self.cleaned_data.get("password2")

        if password1 and password2 and password1 != password2:
            raise forms.ValidationError(
                self.error_messages['password_mismatch'],
                code='Повтор нового пароля не совпадает',
            )
        return self.cleaned_data

  class Meta:
     model = User
     fields = ('username', 'first_name', 'last_name', 'password1',   'password2')

views.py

class CallcenterPasswordChangeView(AbsCallcenterView):
    template_name = 'callcenter/password_change.html'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        patient_pk = kwargs.get('patient_pk')
        patient = get_object_or_404(Patient, pk=patient_pk)
        initial_data = model_to_dict(patient.user)
        context['form'] =CallcenterPasswordChange(initial=initial_data)
        context['patient_pk'] = patient_pk
        context['patient'] = patient
        return context

    def post(self, request, **kwargs):
        context = super().get_context_data(**kwargs)
        patient_pk = kwargs.get('patient_pk')
        patient = get_object_or_404(Patient, pk=patient_pk)
        form = CallcenterPasswordChange(request.POST)
        context['form_user'] = form
        context['patient'] = patient
        if form.is_valid():
            form.save()
        else:
            return render(request, template_name=self.template_name, context=context)

Answer 1

问题解决了！

 class CallcenterPasswordChangeView(AbsCallcenterView):
    template_name = 'callcenter/password_change.html'

   def get_context_data(self, **kwargs):
     context = super().get_context_data(**kwargs)
     patient_pk = kwargs.get('patient_pk')
     patient = get_object_or_404(Patient, pk=patient_pk)
     initial_data = model_to_dict(patient.user)
     context['form'] = CallcenterPasswordChange(initial=initial_data)
     context['patient'] = patient
     return context

 def post(self, request, **kwargs):
     context = super().get_context_data(**kwargs)
     patient = Patient.objects.get(pk=context['patient_pk'])
     form = CallcenterPasswordChange(request.POST)
     context['form'] = form
     if form.is_valid():
         patient.user.set_password(form.cleaned_data['password1'])
         patient.user.save()
         success_url = reverse_lazy('callcenter:patients')
         return HttpResponseRedirect(success_url)

Answer 2

这根本不是你想做的。这试图做的是创建一个全新的用户。

更重要的是，password1 和password2 字段与模型中的实际密码字段无关；另外，没有什么可以处理密码的散列。

你真正想要的是一个只有这两个字段的标准（非模型）表单，然后设置当前用户的密码。

所以形式就是：

class CallcenterPasswordChange(forms.Form):
    password1 = forms.CharField(widget=forms.PasswordInput(),  label='Новый пароль')
    password2 = forms.CharField(widget=forms.PasswordInput(), label='Повтор нового пароля')

    def clean(self):
        password1 = self.cleaned_data.get("password1")
        password2 = self.cleaned_data.get("password2")

        if password1 and password2 and password1 != password2:
            raise forms.ValidationError(
                self.error_messages['password_mismatch'],
                code='Повтор нового пароля не совпадает',
            )
        return self.cleaned_data

在视图中，你这样做：

form = CallcenterPasswordChange(request.POST)
if form.is_valid():
    request.user.set_password(form.cleaned_data['password1'])
    request.user.save()
    return redirect('somewhere')

但是，您还应该注意，Django 已经包含一个密码更改表单和视图。