如何使用 modelformset 上传多个图像 - Django

Question

我正在尝试创建一个系统，该系统允许用户添加新的蔬菜对象、上传缩略图以及多个图像和文件——所有这些都来自 AddVegetable 页面，并且能够轻松地将其作为蔬菜类型输出被过滤以显示在不同的页面上

我正在尝试使用下面的代码来实现这一点，但它不起作用，我无法弄清楚究竟为什么，就目前而言，我得到了 KeyError 'image'，但我不知道为什么。我正在以正确的方式解决这个问题吗？

我暂时忽略图像处理，

models.py

class Vegetable(models.Model):
    title = models.CharField(max_length=0)
    category = models.CharField(max_length=50,
                                choices=CATEGORY_CHOICES)
    description = models.CharField(max_length=1000, null=True)
    thumbnail = models.ImageField(upload_to = 'uploaded_images/')
    attachments = models.FileField(upload_to = uploaded_files/)
    date_added = models.DateTimeField('Date Added', default=datetime.datetime.now)

class VegetableImage(models.Model):
    vegetable = models.ForeignKey(Vegetable, default=None)
    image = models.ImageField(upload_to='images/vegetable',
                             verbose_name='image',)

forms.py

Class AddVegetable(ModelForm):
    class Meta:
          model = Vegetable
          fields = ['title', 'category', 'description', 'thumbnail',
                    'images', 'attachments', 'date_added',]

class ImageForm(ModelForm):
    image = ImageField(label='image')
    class Meta:
        model = VegetableImage
        fields = ['image',]

views.py

def AddVegetable(request):

ImageFormSet = modelformset_factory(VegetableImage,
                                    form=ImageForm, extra=4)

if request.method == 'POST':

    VegetableForm = AddVegetableForm(request.POST)
    formset = ImageFormSet(request.POST, request.FILES,
                           queryset=VegetableImage.objects.none())

    if VegetableForm.is_valid() and formset.is_valid():

        VegetableForm.save()

        for form in formset.cleaned_data:
            image = form['image']
            picture = VegetableImage(vegetable=VegetableForm, image=image)
            picture.save()

        return HttpResponseRedirect('/vegetable/')
    else:
        print (VegetableForm.errors, formset.errors)

else:
    VegetableForm = AddVegetableForm()
    formset = ImageFormSet(queryset=VegetableImage.objects.none())

return render(request, 'vegetable/add.html',
              {'VegetableForm': VegetableForm, 'formset': formset},
              context_instance=RequestContext(request))

模板.html

<form action="/vegetable/add/" method="POST" enctypr="multipart/form-data"> 
{% csrf_token %}
    <table>

            <p> {{ VegetableForm.as_ul }}</p>

            {{ formset.management_form }}
            {% for form in formset %}
            {{ form }}
            {% endfor %}

    </table>

    <input type="submit" value="Post">
</form>

Answer 1

当你调用VegetableForm.save()时，它会返回实例，所以你应该这样做

vegetable = AddVegetableForm.save()

saving objects in a formset 上的文档建议调用formset.save()，它会返回一个实例列表。你可以用commit=False调用save()，设置蔬菜，然后保存到数据库。

images = formset.save(commit=False)
for image in images:
    image.vegetable = vegetable
    image.save()