如何获取在 Django admin 中修改内联模型的用户的 ID？

Question

我有这些 Django 模型（用于酿造的最少数据）：

# models.py
class Author(models.Model):
    name = models.CharField(max_length=100)

class Book(models.Model):
    title = models.CharField(max_length=200)
    author = models.ForeignKey(Author)

class AuditLog(models.Model):
    user = models.ForeignKey(User)  # standard User model
    info = JSONField(default=dict)

我知道如何在 AuthorAdmin 中为 Books 创建内联管理员，但问题是，我需要保存 AuditLog 以及有关谁添加了每个内联对象的信息。

我知道我可以做这样的事情来让用户保存作者：

# admin.py
@admin.register(Author)
class AuthorAdmin(admin.ModelAdmin):
    inlines = [BookInline]

    def save_model(self, request, obj, form, change):
        AuditLog.objects.create(user=request.user, info={'blah': 'blahblah'})
        super().save_model(request, obj, form, change)

但是我应该怎么做才能保存有关使用内联表单集添加新书（例如，一段时间后）的用户的信息？ BaseInlineFormSet 方法不支持这个。

Answer 1

我设法像这样做我想做的事：

# forms.py
class BookInlineFormset(forms.BaseInlineFormset):
    def save_new(self, form, commit=True):
        if commit and hasattr(form, '_context'):
            context = form._context
            user = context['request'].user
            AuditLog.objects.create(user=user)
            # The Proper Way™ is probably to send a custom signal instead.
        return super().save_new(form, commit)


# admin.py
class BookInline(admin.TabularInline):
    formset = forms.BookInlineFormset
    model = Book # you know the drill 

@admin.register(Author)
class AuthorAdmin(admin.ModelAdmin):
    inlines = [BookInline]

    def save_model(self, request, obj, form, change):
        AuditLog.objects.create(user=request.user, info={'blah': 'blahblah'})
        super().save_model(request, obj, form, change)

    def save_formset(self, request, form, formset, change):
        context = {'request', request}
        form._context = context  # just in case
        for form in formset:
            form._context = context
        super().save_formset(request, form, formset, change)

Answer 2

ModelAdmin 和 InlineAdmin 都派生自 BaseModelAdmin，因此您也可以将 save_model 添加到 BookInline。