Django Rest Framework - AssertionError 修复您的 URL conf，或正确设置视图上的 `.lookup_field` 属性

Question

我试图作为特定于用户的单个对象（不是查询集）返回，而无需在请求的 URL 中指定标识符/pk。每个用户都有一个组织 FK。

即http://website/organisation 而不是 http://website/organisation/1

我收到以下错误，因为它需要此标识符： AssertionError: Expected view OrganisationDetail to be called with a URL keyword argument named "user__organisation_id". Fix your URL conf, or set the.lookup_fieldattribute on the view correctly.

在使用 RetrieveModelMixin/GenericAPIView 时我需要如何/需要指定什么，以便它返回由 FK 链接的单个对象？

我的视图类：

class OrganisationDetail(mixins.RetrieveModelMixin, mixins.UpdateModelMixin,generics.GenericAPIView):
    serializer_class = OrganisationDetailSerializer
    lookup_field = 'pk' #yes, I know this is the default and there's no need to speciy

    def get_queryset(self):
        return Organisation.objects.filter(pk=self.request.user.organisation_id)

    def get(self, request, *args, **kwargs):
        return self.retrieve(request, *args, **kwargs)

    def put(self, request, *args, **kwargs):
        return self.update(request, *args, **kwargs)

相关网址： url(r'^api/v1/organisation/$', OrganisationDetail.as_view()),

我的模特：

class Person(AbstractUser):
    organisation = models.ForeignKey(Organisation, related_name='members', null=True)
    is_admin = models.BooleanField(default=False)
    def __str__(self):
        return self.first_name + " " + self.last_name + " - " + self.email

Answer 1

对于详细视图，您需要覆盖 get_object()，而不是 get_queryset()。你仍然需要权限检查，所以我建议通过源代码。首先删除你的 get_queryset() 方法，然后试试这个：

# inside OrganisationDetail
queryset = Organisation.objects.all()

def get_object(self):
    queryset = self.filter_queryset(self.get_queryset())
    # make sure to catch 404's below
    obj = queryset.get(pk=self.request.user.organisation_id)
    self.check_object_permissions(self.request, obj)
    return obj

Answer 2

如果您使用的是 mixins，请将 lookup_field 更改为正确的

class OrganisationDetail(mixins.RetrieveModelMixin, mixins.UpdateModelMixin,generics.GenericAPIView):

    serializer_class = OrganisationDetailSerializer
    lookup_field = 'members' 

    def get(self, request, *args, **kwargs):
        return self.list(request, *args, **kwargs)

    def put(self, request, *args, **kwargs):
        return self.update(request, *args, **kwargs)

    def patch(self, request, *args, **kwargs):
        return self.partial_update(request, *args, **kwargs)

Answer 3

我的解决方案是更改一个参数，它有 id，而不是应该只显示一个元素的路径中的 pk，当将其更改为 时，它的效果非常好

from the django.urls import path
from rest_framework.urlpatterns import format_suffix_patterns
from posts import views


urlpatterns = [
    path ('posts /', views.PublicationList.as_view ()),
    path ('posts / <int: id> /', views.Publication_detail.as_vi`enter code here`ew ()),
]

urlpatterns = format_suffix_patterns (urlpatterns)