【发布时间】:2020-03-12 16:31:58
【问题描述】:
我整天都在研究这个问题,但无法弄清楚我不理解什么 这个简单的程序应该要求用户输入,直到他们输入 9 然后程序退出。
共有 3 个功能。 def main():, def menu():, and def menuInput():
1)def main():-只调用menuInput
2)def menu():-只显示一个菜单
3)def menuInput():-调用要显示的菜单,接受用户输入,测试以确保输入了有效的数字,继续要求用户输入直到做出有效的选择,重复菜单选择直到选择 9。
问题是应该显示整个菜单,然后程序要求用户选择 1-9。如果选择 1,它会显示消息并再次显示菜单,要求输入。
根据我的理解或缺乏,这是迄今为止我使用 cmets 的代码
def main():
#calls menu input
menuInput()
def menu():
#assigns the menu to menuDisplay
menuDisplay = print('''
Welcome! Please make a choice from the following menu
1. Select a year and display available data
2. Review averages by year range
3. Select a date range to display highest
4. Select a date range to display lowest
5. Get total for a selected year range
6. blank
7. blank
8. See this menu again
9. QUIT the program
''')
def menuInput():
#loops until 9 is selected
while True:
try:
userChoice=int(input('Please make a selection: '))
except ValueError:
print('Please enter a whole number less than or equal to 9')
if userChoice > 9:
print('Please enter a number less or equal to 9')
elif userChoice == 0:
print('Please enter a number greater than 0')
elif userChoice == 1:
print('Good')
elif userChoice == 2:
print('Good')
elif userChoice == 3:
print('Good')
elif userChoice == 4:
print('Good')
elif userChoice == 5:
print('Good')
elif userChoice == 6:
print('Good')
elif userChoice == 7:
print('Invalid Choice')
elif userChoice == 8:
print('Good')
else:
print('Thank you! Program Exiting!')
#Calls main
main()
【问题讨论】:
-
你没有描述问题是什么,但是你的
except:ValueError这行不正确,应该是except ValueError:
标签: python