JSON 到 C# 对象（将复杂的 API 响应映射到 C# 对象）

Question

我能够处理简单的 JSON 序列化和反序列化，但这个 API 响应似乎有点复杂，我正在寻求解决这个问题的理想方法的建议。

我正在尝试为 MVC 应用程序调用 API。 目标是将 API 数据映射到模型。 API端点是 https://www.alphavantage.co/query?function=TIME_SERIES_INTRADAY&symbol=MSFT&interval=1min&apikey=MyAPIKey

这里的问题是：

1. JSON 数据键中有空格。
2. 当我尝试在 Visual Studio 中进行特殊粘贴时，它给了我很长时间 每个日期条目的类列表分别，因为这个 API call 返回一组单独的日期信息。

为了解决第 1 点中解释的问题，我在课堂上使用了[JsonProperty("1. Information")]。在我的代码中..

        public async Task TSI()
        {
            HttpClient client = new HttpClient();
            //Uri uri = new Uri("http://date.jsontest.com/");
            Uri uri = new Uri("https://www.alphavantage.co/query?function=TIME_SERIES_INTRADAY&symbol=MSFT&interval=5min&apikey=demo");
            client.DefaultRequestHeaders.Accept.Clear();
            client.DefaultRequestHeaders.Accept.Add(new MediaTypeWithQualityHeaderValue("application/json"));

            HttpResponseMessage response = await client.GetAsync(uri);
            if (response.IsSuccessStatusCode)
            {
                dynamic result = await response.Content.ReadAsAsync<object>();

                IEnumerable<dynamic> dObj = JsonConvert.DeserializeObject<dynamic>(result.ToString());

                IEnumerable<dynamic> t1 = dObj.FirstOrDefault();
                IEnumerable<dynamic> t2 = dObj.LastOrDefault();
                dynamic MetaData = t1.FirstOrDefault();

                Rootobject ro = new Rootobject();
                ro.MetaData = MetaData;

            }

PS：我对 API 调用和处理比较陌生。

我可以打电话给

date.jsontest.com

并将 API 数据映射到模型（我使用特殊粘贴创建的）

//API response
    {
        "time": "12:53:22 PM",
        "milliseconds_since_epoch": 1504875202754,
        "date": "09-08-2017"
    }

//C# code to map to API data
    public class sampleObject
    {
        public string time { get; set; }
        public long milliseconds_since_epoch { get; set; }
        public string date { get; set; }
    }

我的 RootObject 如下所示：

public class Rootobject
    {
        [JsonProperty("Meta Data")]
        public MetaData MetaData { get; set; }

        [JsonProperty("Time Series (1min)")]
        public TimeSeries1Min TimeSeries1min { get; set; }
    }

    public class MetaData
    {
        [JsonProperty("1. Information")]
        public string _1Information { get; set; }

        [JsonProperty("2. Symbol")]
        public string _2Symbol { get; set; }

        [JsonProperty("3. Last Refreshed")]
        public string _3LastRefreshed { get; set; }

        [JsonProperty("4. Interval")]
        public string _4Interval { get; set; }

        [JsonProperty("5. Output Size")]
        public string _5OutputSize { get; set; }

        [JsonProperty("6. Time Zone")]
        public string _6TimeZone { get; set; }
    }

// I have so many of these sub-classes for dates, which again is an issue
    public class TimeSeries1Min
    {
            public _20170907160000 _20170907160000 { get; set; }
            public _20170907155900 _20170907155900 { get; set; }
....
....}



public class _20170907160000
    {
        public string _1open { get; set; }
        public string _2high { get; set; }
        public string _3low { get; set; }
        public string _4close { get; set; }
        public string _5volume { get; set; }
    }

    public class _20170907155900
    {
        public string _1open { get; set; }
        public string _2high { get; set; }
        public string _3low { get; set; }
        public string _4close { get; set; }
        public string _5volume { get; set; }
    }

Answer 1

很难从这个 json 创建模型，但你可以将这些数据转换为字典

var jObj = JObject.Parse(json);
var metadata = jObj["Meta Data"].ToObject<Dictionary<string, string>>();
var timeseries = jObj["Time Series (1min)"].ToObject<Dictionary<string, Dictionary<string, string>>>();

Answer 2

下面的代码应该做你想做的事

       if (response.IsSuccessStatusCode)
        {
            var result = await response.Content.ReadAsStringAsync();

            var obj = JsonConvert.DeserializeObject<Rootobject>(result);
            //No idea what you want to do with this line as there is no MetaData property on the root object
            obj.MetaData = MetaData;

        }