PHP：SQL 值作为文件名

Question

我有这个代码：

    <?php
    $servername = "Jarvis";
    $username = "TonyStark";
    $password = "iLoveIronMan";
    $dbname = "StarkCompany";

    // Create connection
    $conn = new mysqli($servername, $username, $password, $dbname);
    // Check connection
    if ($conn->connect_error) {
        die("Connection failed: " . $conn->connect_error);
    } 

    $sql = "SELECT o.order_id, o.customer_id, op.quantity, op.model FROM oc_order o INNER JOIN oc_order_product op ON o.order_id = op.order_id INNER JOIN oc_product p ON op.product_id = p.product_id WHERE o.order_status_id = 2 AND p.location = 1 ORDER BY o.order_id, op.model";

    $file = fopen('../files/in/filename.csv', 'w');

    if ($rows = mysqli_query($conn, $sql))
    {

        while ($row = mysqli_fetch_assoc($rows))
        {
            fputcsv($file, $row, ';');
        }

        mysqli_free_result($rows);
    }

    mysqli_close($conn);

    fclose($file);
    ?>

现在：我如何以表 o.order_id 的 SQL 值为例，并将该值用作我的文件名？文件名应为 example(o.order_id).csv。这可能吗？

Answer 1

您可以通过这样命名值来让您的生活更轻松：

   $sql = "SELECT o.order_id as filename, o.customer_id, op.quantity, op.model FROM oc_order o INNER JOIN oc_order_product op ON o.order_id = op.order_id INNER JOIN oc_product p ON op.product_id = p.product_id WHERE o.order_status_id = 2 AND p.location = 1 ORDER BY o.order_id, op.model";

那么当你处理行时你可以使用

$rows['filename']