【发布时间】：2020-05-06 12:52:42
【问题描述】：
我正在尝试将文件（在本例中我正在尝试使用图像，但我需要能够上传任何类型的文件，尤其是视频文件）到我的服务器。
这是我的 PHP 代码，它在服务器端运行良好：
<?php include '_config.php';
if ($_FILES["file"]["error"] > 0) {
echo "Error: " .$_FILES["file"]["error"]. "<br>";
} else {
// Check file size
if ($_FILES["file"]["size"] > 20485760) { // 20 MB
echo "ERROR: Your file is larger than 20 MB. Please upload a smaller one.";
} else { uploadImage(); }
}// ./ If
// UPLOAD IMAGE ------------------------------------------
function uploadImage() {
// generate a unique random string
$randomStr = generateRandomString();
$filePath = "uploads/".$randomStr;
// upload image into the 'uploads' folder
move_uploaded_file($_FILES['file']['tmp_name'], $filePath);
// echo the link of the uploaded image
echo $filePath;
}
// GENERATE A RANDOM STRING ---------------------------------------
function generateRandomString() {
$characters = '0123456789abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ';
$charactersLength = strlen($characters);
$randomString = '';
for ($i = 0; $i<20; $i++) {
$randomString .= $characters[rand(0, $charactersLength - 1)];
}
return $randomString."_".$_POST['fileName'];
}
?>
这是我的 Swift 5 函数：
func uploadFile(_ aImage:UIImage, maxWidth:CGFloat, completion: @escaping (_ fileURL:String?) -> Void) {
showHUD()
let image = scaleImageToMaxWidth(image: aImage, newWidth: maxWidth)
// Generate a random filename
var filename = ""
for _ in 0..<20 {
let randomChar = Int(arc4random() % UInt32(charsForRand.count))
filename += charsForRand[randomChar]
}
filename += "__image.jpg"
print("FILENAME: \(filename)")
let boundary = UUID().uuidString
let fieldName = "reqtype"
let fieldValue = "fileupload"
let fieldName2 = "userhash"
let fieldValue2 = "caa3dce4fcb36cfdf9258ad9c"
let config = URLSessionConfiguration.default
let session = URLSession(configuration: config)
var urlRequest = URLRequest(url: URL(string: DATABASE_PATH + "upload-file.php")!)
urlRequest.httpMethod = "POST"
urlRequest.setValue("multipart/form-data; boundary=\(boundary)", forHTTPHeaderField: "Content-Type")
var data = Data()
data.append("\r\n--\(boundary)\r\n".data(using: .utf8)!)
data.append("Content-Disposition: form-data; name=\"\(fieldName)\"\r\n\r\n".data(using: .utf8)!)
data.append("\(fieldValue)".data(using: .utf8)!)
data.append("\r\n--\(boundary)\r\n".data(using: .utf8)!)
data.append("Content-Disposition: form-data; name=\"\(fieldName2)\"\r\n\r\n".data(using: .utf8)!)
data.append("\(fieldValue2)".data(using: .utf8)!)
data.append("\r\n--\(boundary)\r\n".data(using: .utf8)!)
data.append("Content-Disposition: form-data; name=\"fileToUpload\"; fileName=\"\(filename)\"\r\n".data(using: .utf8)!)
data.append("Content-Type: image/png\r\n\r\n".data(using: .utf8)!)
data.append(image.jpegData(compressionQuality: 1.0)!)
data.append("\r\n--\(boundary)--\r\n".data(using: .utf8)!)
// Send a POST request to the URL, with the data we created earlier
session.uploadTask(with: urlRequest, from: data, completionHandler: { responseData, response, error in
if error != nil { print("\(error!.localizedDescription)") }
guard let responseData = responseData else {
DispatchQueue.main.async {
self.simpleAlert("Something went wrong while uploading, try again.")
}
completion(nil)
return
}
if let response = String(data: responseData, encoding: .utf8) {
completion("\(DATABASE_PATH)\(response)")
print("UPLOAD URL: \(DATABASE_PATH)\(response)")
}
}).resume()
}
我在 ViewController 中调用该函数如下：
uploadFile(UIImage(named: "default_avatar")!, maxWidth: 300) { (fileURL) in
if fileURL != nil {
print("FILE URL: \(fileURL!)")
}
}
但这是我在 Xcode 控制台中得到的：
FILE URL: https://example.com/uploads/8iWQOrwr0wgNDor8XNhX_
UPLOAD URL: https://example.com/uploads/8iWQOrwr0wgNDor8XNhX_
这意味着我的函数不会将 "__image.jpg" 字符串附加到 filename 变量，它也不会将我的图像上传到我服务器上的上传文件夹。
我做错了什么？如果我从输入类型为 file 的表单中调用我的 PHP 脚本，它就像一个魅力。所以我的 PHP 脚本很好，所以我肯定在 Swift 函数中做错了什么。
【问题讨论】：
-
我正试图弄清楚这整件事，我希望你的最终答案能引导我找到我的最终答案。显然文件名添加了 __image.jpg，因为它打印出来了。传输中的某个地方是否因为它有一个 _ 字符而将其删除？只是一个想法，但尝试将 __image.jpg 更改为 xximage.jpg 看看是否得到相同的结果。
-
请检查我的答案，我可以弄清楚。