如何在java中找到上传文件的扩展名？

Question

我有以下代码来上传文件，当我使用file.getNeme 时，它显示具有tmp 扩展名的临时文件名，我怎样才能找到实际上传文件的扩展名？我上传的文件名为test.jpg

import java.io.File;
import org.apache.commons.io.FileUtils;

public class FileUploder {

  private File file;

  public File getFile() {
        return file;
  }

  public void setFile(File file) {
        this.file = file;
  }
   ......

  System.out.println("file:" +file.getName());  
  try {
        File fileToCreate = new File(filePath,name);
        FileUtils.copyFile(file, fileToCreate);
  } catch (IOException ex) {
        ex.printStackTrace();
  }

  ......

当前输出类似于 >>> file:upload__1a6d32_13d0eda6d49__7fdf_00000012.tmp

Answer 1

只需添加另一个 getter/setter，如下所示，并删除 getFile() 方法，它就会起作用

私有字符串文件文件名；

public String getFileFileName() {
    return fileFileName;
}

public void setFileFileName(String fileFileName) {
    this.fileFileName = fileFileName;
}

Answer 2

   private String getImageFileExtendtion (FileItem item) {
        String formatName = "png";
        String fileName = item.getName();
        if (fileName != null && fileName.length() >0) {
            int index = -1;
             for (int i = fileName.length()-1 ; i >=0; i --) {
                 if (fileName.charAt(i)=='.') {
                     index = i;
                     break;
                 }
             }
            if (index >=0 && index < fileName.length() -1) {
                 formatName = fileName.substring(index+1);
            }
        }
        return formatName ;
    }

Answer 3

你不应该使用file.getName()

http://struts.apache.org/release/2.0.x/docs/file-upload.html#FileUpload-BasicUsage

setX(File file)  
    The file that contains the content of the uploaded file. This is a temporary file and file.getName() will not return the original name of the file

相反，创建另一个 setter setFileName(String fileName) 应该这样做。