【问题标题】:uploading image to apache tomcat server with android [closed]使用android将图像上传到apache tomcat服务器[关闭]
【发布时间】:2012-01-13 15:41:19
【问题描述】:

我想将图像上传到我的本地 apache tomscat 服务器并正在寻找示例代码。 请让我知道服务器是否允许接收文件以及是否有任何其他方法可以将图像从 android 发送到 apache tomcat 服务器

【问题讨论】:

标签: java android apache tomcat upload


【解决方案1】:

检查一下;)

import java.io.DataOutputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.net.HttpURLConnection;
import java.net.MalformedURLException;
import java.net.URL;

import android.util.Log;

public class HttpFileUploader  {

    URL connectURL;
    String params;
    String responseString;
    String fileName;
    byte[] dataToServer;
    FileInputStream fileInputStream = null;

    HttpFileUploader(String urlString, String params, String fileName) {
        try {
            connectURL = new URL(urlString);
        } catch (Exception ex) {
            Log.i("URL FORMATION", "MALFORMATED URL");
        }
        this.params = params + "=";
        this.fileName = fileName;

    }



    void doStart(FileInputStream stream) {
        fileInputStream = stream;

        String exsistingFileName = "asdf.png";

        String lineEnd = "\r\n";
        String twoHyphens = "--";
        String boundary = "*****";
        String Tag = "3rd";
        try {
            // ------------------ CLIENT REQUEST

            Log.e(Tag, "Starting to bad things");
            // Open a HTTP connection to the URL

            HttpURLConnection conn = (HttpURLConnection) connectURL
                    .openConnection();

            // Allow Inputs
            conn.setDoInput(true);

            // Allow Outputs
            conn.setDoOutput(true);

            // Don't use a cached copy.
            conn.setUseCaches(false);

            // Use a post method.
            conn.setRequestMethod("POST");

            conn.setRequestProperty("Connection", "Keep-Alive");

            conn.setRequestProperty("Content-Type",
                    "multipart/form-data;boundary=" + boundary);

            DataOutputStream dos = new DataOutputStream(conn.getOutputStream());

            dos.writeBytes(twoHyphens + boundary + lineEnd);
            dos
                    .writeBytes("Content-Disposition: form-data; name=\"uploadedfile\";filename=\""
                            + exsistingFileName + "\"" + lineEnd);
            dos.writeBytes(lineEnd);

            Log.e(Tag, "Headers are written");

            // create a buffer of maximum size

            int bytesAvailable = fileInputStream.available();
            int maxBufferSize = 1024;
            int bufferSize = Math.min(bytesAvailable, maxBufferSize);
            byte[] buffer = new byte[bufferSize];

            // read file and write it into form...

            int bytesRead = fileInputStream.read(buffer, 0, bufferSize);

            while (bytesRead > 0) {
                dos.write(buffer, 0, bufferSize);
                bytesAvailable = fileInputStream.available();
                bufferSize = Math.min(bytesAvailable, maxBufferSize);
                bytesRead = fileInputStream.read(buffer, 0, bufferSize);
            }

            // send multipart form data necesssary after file data...

            dos.writeBytes(lineEnd);
            dos.writeBytes(twoHyphens + boundary + twoHyphens + lineEnd);

            // close streams
            Log.e(Tag, "File is written");
            fileInputStream.close();
            dos.flush();

            InputStream is = conn.getInputStream();
            // retrieve the response from server
            int ch;

            StringBuffer b = new StringBuffer();
            while ((ch = is.read()) != -1) {
                b.append((char) ch);
            }
            String s = b.toString();
            Log.i("Response", s);
            dos.close();

        } catch (MalformedURLException ex) {
            Log.e(Tag, "error: " + ex.getMessage(), ex);
        }

        catch (IOException ioe) {
            Log.e(Tag, "error: " + ioe.getMessage(), ioe);
        }
    }

}

【讨论】:

  • 这段代码在我的应用程序中运行,所以在你的应用程序中,应该也可以运行;)别忘了投票,当你将有超过 15 分时;D
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