【问题标题】:Changing a Image source file using php使用 php 更改图像源文件
【发布时间】:2012-03-25 14:00:06
【问题描述】:

我想做一个简单的图片上传,然后把第一张图片换成新上传的照片

php 代码:(为您的帮助发表评论)

<?php

//define a maxim size for the uploaded images in Kb
 define ("MAX_SIZE","100"); 

//This function reads the extension of the file. It is used to determine if the file  is an     image by checking the extension.
function getExtension($str) {
     $i = strrpos($str,".");
     if (!$i) { return ""; }
     $l = strlen($str) - $i;
     $ext = substr($str,$i+1,$l);
     return $ext;
}

//This variable is used as a flag. The value is initialized with 0 (meaning no error  found)  
//and it will be changed to 1 if an errror occures.

//If the error occures the file will not be uploaded.
 $errors=0;
 //checks if the form has been submitted
 if(isset($_POST['Submit'])) 
 {

//reads the name of the file the user submitted for uploading
$image=$_FILES['image']['name'];

//if it is not empty
if ($image) 
{

//get the original name of the file from the clients machine
    $filename = stripslashes($_FILES['image']['name']);

//get the extension of the file in a lower case format
    $extension = getExtension($filename);
    $extension = strtolower($extension);

//if it is not a known extension, we will suppose it is an error and will not      upload the file,  
//otherwise we will do more tests
if (($extension != "jpg") && ($extension != "jpeg") && ($extension != "png") &&              ($extension != "gif")) 
    {

//print error message

echo "";

        $errors=1;
    }
    else
    {
//get the size of the image in bytes
//$_FILES['image']['tmp_name'] is the temporary filename of the file
//in which the uploaded file was stored on the server
$size=filesize($_FILES['image']['tmp_name']);

//compare the size with the maxim size we defined and print error if bigger
if ($size > MAX_SIZE*1024)
{
echo "";

$errors=1;
}
//we will give an unique name, for example the time in unix time format
$image_name=time().'.'.$extension;

//the new name will be containing the full path where will be stored (images folder)
$newname="images/".$image_name;

//we verify if the image has been uploaded, and print error instead
$copied = copy($_FILES['image']['tmp_name'], $newname);
if (!$copied) 
{
echo "";

$errors=1;
}}}}

//If no errors registred, print the success message
if(isset($_POST['Submit']) && !$errors) 
{
echo "";
}

?>

-摄影部

<div id="photo1div">
<img id="photo1" src=""  alt="No Image" width="251" height="146" />
</div>

-按钮(上传和浏览)

<form name="newad" method="post" enctype="multipart/form-data"  action="">
  <table>
  <tr><td><table>
    <tr>
      <td><input type="file" name="image" /></td>
    </tr>
    <tr>
      <td><input name="Submit" id="upload" type="submit" value="Upload image"     onclick"load_images()" /></td>
    </tr>
  </table></td></tr>
  </table>
</form>

-如果你有更好的方法我可以做到这一点(如 jquery 或 ajax) 请务必告诉我怎么做

Php 和所有的都在同一个文件中(.php 扩展名)

所以评论:

当我单击“浏览”并选择一个图像时,它会保存到名为“image”的目录文件夹中/然后当我单击“提交”时,我希望它将图像源 (photo1) 更改为我刚刚上传的图像。

我有什么办法可以做到这一点?

谢谢 -朱利安

【问题讨论】:

  • 我的意思是,检查您已经提出的问题,并接受一些答案。

标签: php upload submit photo


【解决方案1】:

这是我的解决方案

在您拥有表单元素的页面中:-

  <form id="imageUploadForm" action="storeImage.php" method="POST" enctype="multipart/form-data"> 

         <input  type="file"name="imgFile" >  

         <input type="submit value="Upload">

  </form>   

在您的storeImage.php 中执行以下操作

if($_SERVER["REQUEST_METHOD"]=="POST"&&isset($_REQUEST["imgFile"]))
{          
   $name=$_FILES["imgFile"]["name"];

   $tempName=$_FILES["imgFile"]["tmp_name"]; // temporary location

   $size=$_FILES["imgFile"]["size"];

   $type=$_FILES["imgFile"]["type"];

   if(($type=="image/jpg"||$type=="image/jpeg"||$type=="image/png")&&($size>0&&$size<=4096000))
   {

      $dir="thisImageFolder";  //folder name in your current directory where the file will be stored

      $fullDirectory=$dir;

      $realPath=$dir."/".$name;

       if(is_dir($fullDirectory))  //if directory exists then move the file to this plae
       {
        move_uploaded_file($tempName, $realPath);


       }
       else   //else make the directory and the move the file to this place
       {
        mkdir($fullDirectory,0777,true);

        move_uploaded_file($tempName, $realPath);

       }

         header("Location:backToMyPage.php");  //takes the user back to this page.
   }


    else
{  
  print "File not of an image type or has exceeded size limit";  
} 
}

当您返回页面时,只需使用图像的相对路径即可加载。

【讨论】:

  • 阅读我的问题的最底部,php和所有其他材料都在同一个文件中(photo_upload.php)
  • 然后只需将表单的action 替换为“”即可使其自行提交到同一个脚本
  • 这不是编程问题。我不知道你为什么会这样问
  • 你给我的例子中的所有文字都是红色的,也许你的例子中缺少“?
  • 查看 if($_SERVER["REQUEST_METHOD"]=="POST&&isset($_REQUEST["imgFile"])) { 您在该区域内缺少一个 "
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