如何使用 PATCH 方法通过 Ajax 使用 django sweetpie 创建多个对象？答案

【问题标题】：How to create multiple objects with django tastypie via Ajax using the PATCH method?如何使用 PATCH 方法通过 Ajax 使用 django sweetpie 创建多个对象？
【发布时间】：2014-05-11 03:11:18
【问题描述】：

尝试使用 Jquery 和它的失败警报 Not connect 创建多个对象，如下面的代码所示。但是使用传递给 ajax 的相同数据 (sent_data) 使用 curl 执行请求，效果很好。

sent_data = {"objects":[{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]},{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]}]};

$.ajax({
        type:'POST',
        url:'http://localhost:8000/api/v1/order/',
        contentType: 'application/json',
        data:sent_data,
        headers:{'X-HTTP-Method-Override':'PATCH'},
        dataType:'json',
        processData:false,
        success: function(data){
            alert("POST request made");

        },
        error: function(jqXHR,exception){
            if (jqXHR.status === 0) {
                alert('Not connect.\n Verify Network.');
            } else if (jqXHR.status == 404) {
                alert('Requested page not found. [404]');
            } else if (jqXHR.status == 500) {
                alert('Internal Server Error [500].');
            } else if (exception === 'parsererror') {
                alert('Requested JSON parse failed.');
            } else if (exception === 'timeout') {
                alert('Time out error.');
            } else if (exception === 'abort') {
                alert('Ajax request aborted.');
            } else {
                alert('Uncaught Error.\n' + jqXHR.responseText);
            }
        }
    });

查看django-tastypie PATCH gives me a "400 (Bad Request)" 和Ajax Post Request to TastyPie Doesn't Do Anything 发现，由于我正在尝试进行文档中提到的批量操作，因此我不得不使用“PATCH”方法，我通过提供 X-HTTP-Method-Override 来做到这一点头，但一切都是徒劳的。我可能错过了什么？

【问题讨论】：

标签： ajax django tastypie

【解决方案1】：

在做了更多研究之后，我发现问题是我没有在表单中为“CSRFToken”设置标题，这个要点here 帮助我弄清楚了。所以工作请求看起来像这样，

sent_data = JSON.stringify({"objects":[{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]},{"shopping_id":"#3Q^9%LF728N!9*840H(NEAH2L%J8$3H2J35(ZI@32MSA!S@RD%D3#PQG9^2#*J69S4&7IJX)POV$PYQ70817P2C!6OEPA%*$WR7","quantity":"3","option":"/api/v1/option/2/","item":"/api/v1/item/1/","created_by":"/api/v1/user/-1/","modified_by":"/api/v1/user/-1/","toppings_and_extras":["/api/v1/topping/1/","/api/v1/topping/2/"]}]});

$.ajax({
        url:'/api/v1/order/?format=json',
        accepts:'application/json',
        contentType: 'application/json',
        headers:{
            'X-HTTP-Method-Override':'PATCH'
        },
        method:'POST',
        data:sent_data,
        beforeSend:function(jqXHR,settings){
            jqXHR.setRequestHeader('X-CSRFToken',$("input[name=csrfmiddlewaretoken]").val())
        },
        dataType:'json',
        processData:false,
        success: function(data){
            alert("damn posted");

        },
        error: function(jqXHR,exception){
            if (jqXHR.status === 0) {
                alert('Not connect.\n Verify Network.');
            } else if (jqXHR.status == 404) {
                alert('Requested page not found. [404]');
            } else if (jqXHR.status == 500) {
                alert('Internal Server Error [500].');
            } else if (exception === 'parsererror') {
                alert('Requested JSON parse failed.');
            } else if (exception === 'timeout') {
                alert('Time out error.');
            } else if (exception === 'abort') {
                alert('Ajax request aborted.');
            } else {
                alert('Uncaught Error.\n' + jqXHR.responseText);
            }
        }
    });

还要注意我传递给了 JSON.stringify() 方法。

【讨论】：