【发布时间】:2017-11-01 07:18:33
【问题描述】:
我正在开发我在 laravel 中的第一个项目,现在我执行搜索功能,但是,我正在执行一个涉及多个左连接的查询,并且在搜索时返回了一些冗余信息。
相关表就是这四个,查询如下:
$searchData = ProfessionalDetail::select('u.id as user_id','u.first_name','u.last_name','u.profile_pic','c.name as city_name','professional_details.avg_ratings')
->join('users as u' , 'u.id', '=' ,'professional_details.user_id')
->join('user_speciality as us' , 'us.user_id', '=' ,'professional_details.user_id')
->join('specialities as sp' , 'sp.id', '=' ,'us.speciality_id')
->join('cities as c' , 'c.id', '=' ,'professional_details.city_id')
->join('users_roles as ur' , 'ur.user_id', '=' ,'professional_details.user_id')
->where( function ( $q2 ) use ( $name) {
$q2->where('u.first_name' , 'like', '%' . $name . '%')
->orWhere('u.last_name','like', '%'.$name.'%')
->orWhere('u.first_name','like',$name.'%');
->orWhere('sp.name','like',$name.'%');
})
->where('ur.role_id' ,'=' , 2)
->paginate($num_per_page);
return $searchData;[![demo][1]][1]
我尝试的是,按名称或专业(这是一个医生页面)列出用户,当按专业准备好后一切顺利。但是当我想按用户列出时,左加入“user_speciality”和“professional_details”。这会多次返回我的用户。
例如:
public function testApi(Request $request)
{
$users = ProfessionalDetail::searchByNameAndSpe("joshi", 10);
$i = 0;
if ($users) {
foreach ($users as $key => $value) {
$response["result"][] = $value;
$response["total"] = $i++;
}
} else {
return "error";
}
return $response;
}
返回:
{"result":[{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Skin Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Heart Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"ENT Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Kidney Specialist","city_name":"Pune","avg_ratings":"0.00"},{"user_id":204,"first_name":"Joshi","last_name":"Mohit","profile_pic":"1495436016.jpg","name":"Eye Specialist","city_name":"Pune","avg_ratings":"0.00"}],"total":4}
Joshi只注册了一次,但我知道他会因为“多对多”的关系而被多次返回,因为他拥有多个专业。
现在,要让它按专业和用户名进行搜索,我知道的唯一方法是使用左连接,我认为分离信息的一种方法是在控制器中处理数组的信息, 但是我想知道这是否可以在查询中解决,因为我对 SQL 不太了解,如果有任何方法我将非常感激,因为它可以节省我调试所有信息的许多步骤。
每个模型的方法
UserSpeciality 表
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'speciality_id', 'user_id');
}
用户
public function userSpeciality() {
return $this->belongsToMany('App\Speciality','user_speciality', 'user_id', 'speciality_id');
}
专业
public function users() {
return $this->belongsToMany('App\User', 'user_speciality', 'user_id', 'speciality_id');
}
专业明细表
public function user(){
return $this->belongsTo("App\User");
}
【问题讨论】:
-
您是否为这些表设置了模型?
-
如果和每个人都有对应的关系方法,我已经修改了帖子并添加了它们
标签: php mysql sql laravel search