这两个查询之间的区别

Question

我正在运行 2 个查询，应该会显示相同的结果，

第一个查询：

SELECT count( id ) AS cv FROM table_name WHERE field_name LIKE '%êêê01, word02, word03%'

第二次查询：

SELECT count( id ) AS cv FROM table_name WHERE match(field_name) against('êêê01, word02, word03')

但是第一个显示的行比第二个多，有人可以告诉我为什么吗？

我在这个字段上使用全文索引，

谢谢。

Answer 1

我做了一个快速的research，下面的引用应该回答你的问题：

One problem with MATCH on MySQL is that it seems to only match against whole words so a search for 'bla' won't match a column with a value of 'blah'.

documentation for match中也有描述

By default, the MATCH() function performs a natural language search for a string against a text collection. A collection is a set of one or more columns included in a FULLTEXT index. The search string is given as the argument to AGAINST(). For each row in the table, MATCH() returns a relevance value; that is, a similarity measure between the search string and the text in that row in the columns named in the MATCH() list.

同时like 更“强大”，因为它可以查看单个字符：

Per the SQL standard, LIKE performs matching on a per-character basis, thus it can produce results different from the = comparison operator:

这就解释了为什么like 返回的结果比match 多。