PHP - Array_diff 具有两个不同维度的数组

Question

我有这 2 个数组：

$haystack = array("rowid" => array("100", "200"), "description" => array ("something", "something else"));
$needle = array("rowid" => array("200", "300", "400"), "description" => array ("something else", "other", "other else"), "test" => "bye");

我想用 $needle 和 $haystack 做一个 array_diff，但我得到一个错误，因为 $needle 数组是多维的，但“测试”键只有一维：

foreach ($needle as $key => $value) :
$left[$key] = array_diff($needle[$key],$haystack[$key]);
endforeach;

警告：array_diff()：参数 #1 不是数组
警告： array_diff(): 参数 #2 不是数组

我该如何解决这个问题？ 我只需要在 $left 数组中维护“rowid”和“description”值（我可以丢弃“test”值）。

$left 应该是：

Array
(
    [rowid] => Array
        (
            [0] => 300
            [1] => 400
        )

    [description] => Array
        (
            [0] => other
            [1] => other else
        )

) 

感谢您的帮助！

Answer 1

删除“测试”=>“再见”；从 $needle 或以正确的方式编写它们。

//array_diff takes arguments as array.
foreach ($needle as $key => $value) :
$left[$key] = array_diff($needle[$key],$haystack[$key]);
//when $key = test $needle[$key]=bye which is not array 
//thats why you got Warning: array_diff(): Argument #1 is not an array  this warning

//again when $key=test ,$haystack[$key]=null which is not array
//thats why you got Warning: array_diff(): Argument #2 is not an array
endforeach;